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The problem:
A ball accelerates at 8 cm/s^2 for 3 seconds, starting with velocity 12 cm/s.
• To figure this out you must take the acceleration formula and manipulate algrebically to give you V2=V1+(a*’dt). This will then give you 36cm/s
• Assuming that acceleration is constant, what will be its average velocity during this interval?
Here you will just take your V2-V1/2 which is (36cm/s-12cm/s)/2=18cm/s
• How far will it travel during this interval?
To find displacement
‘ds=Vavg/’dt this gives you (18cm/s)/(3s)=6cm
(18 cm/s) / (3 s) = 6 (cm/s)/s = 6 (cm/s) * (1/s) = 6 cm/s^2. The units calculation should have tipped you off to the error.
Something that averages 18 cm/s for 3 s is going to move more than 6 cm.
Both forms of reasoning should have been used to check your result, and either would have shown you that there is an error here.
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10 min
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