course phy 121
Question: `q001. There are 9 questions and 4 summary questions in this assignment. What is the volume of a rectangular solid whose dimensions are exactly 3 cm by 5 cm by 7 cm?
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Your solution:
35 * 3 m^3 = 105 m^3.
confidence rating #$&* ok
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Self-critique (if necessary): ok
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Question: `q002. What is the volume of a rectangular solid whose base area is 48 square meters and whose altitude is 2 meters?
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Your solution:
48 m^2 * 2 m = 96 m^3.
confidence rating #$&* ok
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Self-critique (if necessary): ok
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Question: `q003. What is the volume of a uniform cylinder whose base area is 20 square meters and whose altitude is 40 meters?
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Your solution:
20 m^2 * 40 m = 800 m^3.
confidence rating #$&* ok
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Self-critique (if necessary): ok
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Question: `q004. What is the volume of a uniform cylinder whose base has radius 5 cm and whose altitude is 30 cm?
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Your solution:
25 pi cm^2 * 30 cm = 750 pi cm^2
confidence rating #$&* ok
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Self-critique (if necessary): ok
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Question: `q005. Estimate the dimensions of a metal can containing food. What is its volume, as indicated by your estimates?
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Your solution:
(9 pi / 4) in^2 * 5 in = 45 pi / 4 in^3.
=35 in^3.
confidence rating #$&* ok
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Self-critique (if necessary): ok
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Self-critique rating #$&* ok
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Question: `q006. What is the volume of a pyramid whose base area is 50 square cm and whose altitude is 60 cm?
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Your solution:
1/3 * 50 cm^2 * 60 cm = 1000 cm^3.
confidence rating #$&*
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Question: `q007. What is the volume of a cone whose base area is 20 square meters and whose altitude is 9 meters?
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Your solution:
1/3 A * h = 1/3 * 20 m^2 * 9 m = 60 m^3.
confidence rating #$&* ok
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Self-critique (if necessary): ok
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Question: `q008. What is a volume of a sphere whose radius is 4 meters?
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Your solution:
4/3 pi * (4 m)^3 = 4/3 pi * 4^3 m^3 = 256/3 pi m^3.
confidence rating #$&*: ok
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Self-critique (if necessary): ok
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Question: `q009. What is the volume of a planet whose diameter is 14,000 km?
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Your solution:
4/3 pi r^3 = 4/3 pi * (7,000 km)^3 = 4/3 pi * 343,000,000,000 km^3 = 1,372,000,000,000 / 3 * pi km^3.
confidence rating #$&* ok
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Self-critique (if necessary): ok
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Self-critique rating #$&* ok
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Question: `q010. Summary Question 1: What basic principle do we apply to find the volume of a uniform cylinder of known dimensions?
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Your solution:
The principle is that when the cross-section of an object is constant, its volume is V = A * h, where A is the cross-sectional area and h the altitude. Altitude is measure perpendicular to the cross-section.
confidence rating #$&* ok
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Self-critique (if necessary): ok
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Question: `q011. Summary Question 2: What basic principle do we apply to find the volume of a pyramid or a cone?
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Your solution:
The volumes of these solids are each 1/3 the volume of the enclosing figure. Each volume can be expressed as V = 1/3 A * h, where A is the area of the base and h the altitude as measured perpendicular to the base.
confidence rating #$&*ok
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Self-critique (if necessary): ok
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Self-critique rating #$&* ok
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Question: `q012. Summary Question 3: What is the formula for the volume of a sphere?
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Your solution:
The volume of a sphere is V = 4/3 pi r^3, where r is the radius of the sphere
confidence rating #$&* ok
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Self-critique (if necessary): ok
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Question: `q013. Explain how you have organized your knowledge of the principles illustrated by the exercises in this assignment.
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Self-critique (if necessary):
These examples were refresher
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Self-critique rating #$&* ok
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