QUIZ 2

course PHY 121

Reason out the quantities v0, vf, v, vAve, a, s and t: If an object’s velocity changes at a uniform rate from 8 cm/s to 11 cm/s as it travels 38 cm, then what is the average acceleration of the object?Using the equations which govern uniformly accelerated motion determine vf, v0, a, s and t for an object which accelerates through a distance of 38 cm, starting from velocity 8 cm/s and accelerating at .75 cm/s/s.

#$&* d= 38cm, Vo = 8cm/s, Vf=11cm/s

V^2=Vo^2+2ad

11^2=8^2+2*a*38

121=64+76a

57=76a

A= 57/76 = 0.75cm/s^2

A=vf-V0/dt

Dt=vf-Vo/a

=11-8/0.75

=4sec

&#This looks good. Let me know if you have any questions. &#

#$&*