course phy 122
Create a single light sourceFocal distance is 12.5 cm
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Lens to screen is 12 cm
Lens to light is 80 cm
For the 50 cm away:
Lens to screen is 14 cm
For the 40 cm away:
Lens to screen is 19 cm
For the 30 cm away:
Lens to screen is 32 cm
For the 20 cm away:
Lens to screen is 60 cm
Create image of a double light source
Light to lens is 50 cm, and lens to screen is 33 cm.
Separation of the flames is 4 cm, and separation of image is 3 cm.
If you cover the left flame, the right image disappears because the light goes into the source and cross and exit on the other side, the light source to lens and then reflection make and X. Meaning at the point of the X the image follows a straight line.
Light to lens is 30 cm, and lens to screen is 34 cm.
Separation of the flames is 4 cm, and separation of the image is 7 cm.
Light to lens is 20 cm, and lens to screen is 36 cm.
Separation of the flames is 4 cm, and separation of the image is 12 cm.
Within 3 cm of focal distance, lens to screen is 55 cm.
Distance of 1 cm outside the focal distance, lens to screen is 64 cm.
Make a spotlight
The focal distance is the same as the original focal distance. Yes the sharpness and shape changes with the distance changing.
Create an image
Screen to object is 28cm, object to first lens is 39 cm, first lens to second lens is11 cm, and second lens to candle is 4.5 cm.
Analyze the results:
1/f=1/i+1/o
1/20=1/28+1/39
0.05=0.06, not the same, but close due to error.
i/o=28/39=0.717
The object was 7 cm in size and the image was 5 cm. This would give us a ratio of 5/7 which is 0.714.
I don’t know how to figure this without the information of the object distance and the image distance for the candle to screen scenario. Could you please explain it to me.
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Good work, though it's not clear what it is you are trying to figure out with your last question.
Let me know if you have questions.