Phy 121
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An automobile rolls 10 meters down a constant incline with slope .05 in 8 seconds, starting from rest. The same automobile requires 5 seconds to roll the same distance down an incline with slope .10, again starting from rest.
• At what average rate is the automobile's acceleration changing with respect to the slope of the incline?
answer/question/discussion: ->->->->->->->->->->->-> : `ds = v0`dt + .5a`dt^2; a = (`ds – v0`dt) / (.5 * `dt^2); a = (10 m – 0 m/s * 8 s) / [.5 * (8 s)^2]; a = 10 m / 32 s^2 = .3125 m / s^2 and a = 10 m / [.5 * (5 s)^2]; a = 10 m / 12.5 s^2; a = .8 m/s^2; therefore, rate of change acceleration with respect to slope = (.8 m/s^2 - .3125 m/s^2) / (.1 - .05) = .4875 m/s^2 / .05 = 9.75 m/s^2 for every 1 change in slope.
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15 minutes
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&#Very good responses. Let me know if you have questions. &#