Phy 121
Your 'cq_1_12.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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Masses of 5 kg and 6 kg are suspended from opposite sides of a light frictionless pulley and are released.
• What will be the net force on the 2-mass system and what will be the magnitude and direction of its acceleration?
answer/question/discussion: ->->->->->->->->->->->-> : Fnet = 9.8 N; a = .89 m/s^2
F1 = 5 kg * 9.8 m/s^2 = 49 kg * m/s^2 = 49 N
F2 = 6 kg * 9.8 m/s^2 = 58.8 kg * m/s^2 = 58.8 N
Fnet = 58.8 N – 49 N = 9.8 N
9.8 N = 11 kg * a
A = 9.8 kg * m/s^2 / 11 kg
A = .89 m/s^2
• If you give the system a push so that at the instant of release the 5 kg object is descending at 1.8 meters / second, what will be the speed and direction of motion of the 5 kg mass 1 second later?
answer/question/discussion: ->->->->->->->->->->->-> : The 5 kg object will start descending at 1.8 meters / second but will be accelerating at .89 m/s^2 in the opposite direction, therefore slowing it down, so one second later it will still be descending but at .91 m/s^2 and slowing.
• During the first second, are the velocity and acceleration of the system in the same direction or in opposite directions, and does the system slow down or speed up?
answer/question/discussion: ->->->->->->->->->->->-> : During the first second the velocity and acceleration are in opposite directions I think. The system is slowing down.
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5 minutes
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Good. No revision is necessary, but check the discussion at the link:
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Solution
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