course Mth 163 c튢}assignment #008
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20:28:09 `q001. Note that this assignment has 4 questions For the function y = 1.1 x + .8, what are the coordinates of the x = 2 and x = 9 points? What is the rise between these points and what is the run between these points? What therefore is the slope between these points?
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RESPONSE --> When the first equation has the x value as 2, the coordinates are (2,3). And when the x value is 9, the coordinates are (9,10.7).The rise between the points 7 and the run is 7.7. confidence assessment: 1
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20:29:51 Evaluating y = 1.1 x +.8 for x = 2 and x = 9 we obtain y = 3 and y = 10.7. The graph points are therefore (2,3) and (9,10.7). The rise between these points is 10.7 - 3 = 7.7 and the run is 9-2 = 7. Thus the slope is 7.7 / 7 = 1.1.
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RESPONSE --> To get a slope we take the rise divided by the run which here is 1.1. self critique assessment: 2
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qާ`ڑ|Sx assignment #008 008. Precalculus I 09-25-2008
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22:08:24 `q001. Note that this assignment has 4 questions For the function y = 1.1 x + .8, what are the coordinates of the x = 2 and x = 9 points? What is the rise between these points and what is the run between these points? What therefore is the slope between these points?
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RESPONSE --> When we first solve to find the first equation, the x value of 2 makes the coordinates (2,3). And the second equation with the x value of 9 makes a coordinate of (9,10.7). The run from the two points is 7 while the the rise of the two points is 7.7. When we look for the slope between the two points, the formula is rise/ run so the slope here is 1.1. confidence assessment: 2
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22:14:46 Evaluating y = 1.1 x +.8 for x = 2 and x = 9 we obtain y = 3 and y = 10.7. The graph points are therefore (2,3) and (9,10.7). The rise between these points is 10.7 - 3 = 7.7 and the run is 9-2 = 7. Thus the slope is 7.7 / 7 = 1.1.
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RESPONSE --> ok self critique assessment: 3
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22:26:42 `q002. For the function y = 1.1 x + .8, what are the coordinates of the x = a point, in terms of the symbol a? What are the coordinates of the x = b point, in terms of the symbol b?
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RESPONSE --> The coordinates for the first equation are (a,9.1) and the second equation are (b,9.1). confidence assessment: 1
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22:38:33 If x = a, then y = 1.1 x + .8 gives us y = 1.1 a + .8. If x = b, then y = 1.1 x + .8 gives us y = 1.1 b + .8. Thus the coordinates of the x = a point are (a, 1.1 a + .8) and (b, 1.1 b + .8).
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RESPONSE --> the equations here are not to be solved so I presumed that they are to be solved all the way though we want to leave the equations alone to find the unknown variables. self critique assessment: 2
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22:45:43 `q003. We see that the coordinates of the x = a point are (a, 1.1 a + .8) and (b, 1.1 b + .8). What therefore is the rise between these two points? What is the run between these two points?
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RESPONSE --> The rise would be ( 11b+.8)/ (11a+.8) and the run would be a/b. confidence assessment: 1
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22:47:12 The rise between the points is the rise from y = 1.1 a + .8 to y = 1.1 b + .8, a rise of rise = (1.1 b + .8) -(1.1 a + .8) = 1.1 b + .8 - 1.1 a - .8 = 1.1 b - 1.1 a. The run is from x = a to x = b, a run of run = b - a.
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RESPONSE --> ok self critique assessment: 1
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22:58:33 `q004. We see that the rise between the x = a and x = b points of the graph of y = 1.1x +.8 is 1.1 b + .8 - (1.1 a + .8), while the run is b - a. What therefore is the average slope of the graph between these points? Simplify your answer.
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RESPONSE --> i think that the average slope would be the points of the rise and run? confidence assessment: 1
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22:58:48 The slope is slope = rise / run = (1.1 b - 1.1 a) / (b - a) = 1.1 (b - a) / (b - a) = 1.1. The significance of this series of exercises is that the slope between any two points of the straight line y = 1.1 x + .8 must be 1.1, no matter whether the points are given by numbers (e.g., x = 2 and x = 9) or by symbols (x = a and x = b). Mostly
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RESPONSE --> ok self critique assessment: 2
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