course Phy 231
6/8 5:45
Randomized QuestionAssignment 3Version 4What are the acceleration and final velocity of an object whose average velocity, accelerating uniformly from rest for 7.9 seconds, is 59 cm/s? How far does the object travel during the 7.9 seconds?
Final velocity, after starting from rest = 2*average velocity =
2*59 cm/s = 118 cm/s
Acceleration = change in velocity / time = (118 cm/s – 0 cm/s) / (7.9 sec) =
118cm/s / 7.9 sec = 14.9 cm/s^2
Distance travelled = area of the trapezoid under the graph = average velocity*time interval = ½(0cm/s+118cm/s)*7.9s =
59 cm/s * 7.9 s =
466.1 cm or
470 cm (with the correct significant figures)
"
&#Very good work. Let me know if you have questions. &#
#$&*