Phy 231
Your 'cq_1_02.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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The problem:
A ball starts with velocity 4 cm/sec and ends with a velocity of 10 cm/sec.
• What is your best guess about the ball's average velocity?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The average velocity would be the average of the two given velocities: 4 cm/s +10 cm/s / 2 = 14 cm/s / 2 = 7 cm/s.
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• Without further information, why is this just a guess?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
This is just a guess because we do not know how long it took for the velocity to change from 4 to 10 cm/s. Also, we do not know is the acceleration was constant for the object, which would change the average.
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• If it takes 3 seconds to get from the first velocity to the second, then what is your best guess about how far it traveled during that time?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
To find distance travelled, you multiply the velocity by the time interval: 7 cm/s * 3 s = 21 cm.
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• At what average rate did its velocity change with respect to clock time during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
Average rate of change is the change in velocity / change in clock time = 10 cm/s – 4 cm/s / 3 seconds = 6 cm/s / 3 s = 2 cm/s^2.
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20 minutes
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&#Very good work. Let me know if you have questions. &#