Phy 231
Your 'cq_1_04.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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The problem:
A ball is moving at 10 cm/s when clock time is 4 seconds, and at 40 cm/s when clock time is 9 seconds.
• Sketch a v vs. t graph and represent these two events by the points (4 sec, 10 cm/s) and (9 s, 40 cm/s).
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The first point on the graph is (4, 10). The second point is (9,40). The second point is 5 units to the left of and 30 units higher than the first point.
#$&*
• Sketch a straight line segment between these points.
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The graph made by connecting the points is an increasing straight line. It is not very steep, but it is not flat either.
#$&*
• What are the rise, run and slope of this segment?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
Rise: 30 cm/s
Run: 5 sec
Slope = 30 cm/s / 5s = 6cm/s^2. This is the acceleration of the object in the time interval.
#$&*
• What is the area of the graph beneath this segment?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The area of the trapezoid under the graph is 1/2(10+40cm/s)*5s = 125 square units
This number means that the object moved 125 cm in the time interval.
#$&*
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10 minutes
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&#Your work looks very good. Let me know if you have any questions. &#
Phy 231
Your 'cq_1_04.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** **
The problem:
A ball is moving at 10 cm/s when clock time is 4 seconds, and at 40 cm/s when clock time is 9 seconds.
• Sketch a v vs. t graph and represent these two events by the points (4 sec, 10 cm/s) and (9 s, 40 cm/s).
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The first point on the graph is (4, 10). The second point is (9,40). The second point is 5 units to the left of and 30 units higher than the first point.
#$&*
• Sketch a straight line segment between these points.
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The graph made by connecting the points is an increasing straight line. It is not very steep, but it is not flat either.
#$&*
• What are the rise, run and slope of this segment?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
Rise: 30 cm/s
Run: 5 sec
Slope = 30 cm/s / 5s = 6cm/s^2. This is the acceleration of the object in the time interval.
#$&*
• What is the area of the graph beneath this segment?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The area of the trapezoid under the graph is 1/2(10+40cm/s)*5s = 125 square units
This number means that the object moved 125 cm in the time interval.
#$&*
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10 minutes
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&#Your work looks very good. Let me know if you have any questions. &#