Phy 231
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An automobile rolls 10 meters down a constant incline with slope .05 in 8 seconds, starting from rest. The same automobile requires 5 seconds to roll the same distance down an incline with slope .10, again starting from rest.
• At what average rate is the automobile's acceleration changing with respect to the slope of the incline?
answer/question/discussion: ->->->->->->->->->->->-> :
Situation 1: vAve = 10m/8sec = 1.25m/s
Vf = 2(1.25ms/) = 2.5m/s
Acceleration = 2.5m/s / 8s = .3125m/s^2
Situation 2: vAve = 10m / 5s = 2m/s
Vf= 2(2m/s) = 4m/s
Acceleration = 4m/s / 5s = .8m/s^2
Change in acceleration = .8m/s^2 - .3125m/s^2 = .4875m/s^2
Change in slope = .1-.05 = .05
Change in acceleration with respect to slope = .4875m/s^2 / .05 = 9.75m/s^2
#$&*
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15 minutes
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