Phy 231
Your 'cq_1_12.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** **
Masses of 5 kg and 6 kg are suspended from opposite sides of a light frictionless pulley and are released.
• What will be the net force on the 2-mass system and what will be the magnitude and direction of its acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
Side 1: 9.8m/s^2 (5kg) = 49N
Side 2: 9.8m/s^2 (6kg) = 58.5N
Net Force = 58.5N-49N = 9.8N
9.8N = 11kg(acceleration)
A = 9.8 m/s^2 kg / 11kg = .891m/s^2 toward the ground
#$&*
• If you give the system a push so that at the instant of release the 5 kg object is descending at 1.8 meters / second, what will be the speed and direction of motion of the 5 kg mass 1 second later?
answer/question/discussion: ->->->->->->->->->->->-> :
vf = -1.8m/s+9.8m/s^2 (1s)
vf = 8m/s
The 5kg object will be moving at 8m/s up: the opposite direction from what it was going before.
the system doesn't accelerate at 9.8 m/s^2
#$&*
• During the first second, are the velocity and acceleration of the system in the same direction or in opposite directions, and does the system slow down or speed up?
answer/question/discussion: ->->->->->->->->->->->-> :
For the first part of the time interval the velocity and the acceleration were in opposite direction, but in the middle, the velocity changed direction and then went in the same direction as the acceleration. The velocity is decreasing / becoming less negative. Then it is 0m/s for a moment and then it begins to increase at 9m/s^2 for the rest of the interval.
#$&*
** **
20 minutes
** **
&#See any notes I might have inserted into your document. If there are no notes, this does not mean that your solution is completely correct.
Then please compare your solutions with the expanded discussion at the link
Solution
Self-critique your solutions, if this is necessary, according to the usual criteria. Insert any revisions, questions, etc. into a copy of this posted document. Mark any insertions with &&&& so they can be easily identified.If your solution is completely consistent with the given solution, you need do nothing further with this problem. &#