Phy 231
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A steel ball of mass 60 grams, moving at 80 cm / sec, collides with a stationary marble of mass 20 grams. As a result of the collision the steel ball slows to 50 cm / sec and the marble speeds up to 70 cm / sec.
• Is the total momentum of the system after collision the same as the total momentum before?
answer/question/discussion: ->->->->->->->->->->->-> :
.06kg*.8m/s + .02kg*0m/s = .048 kg m/s
.06kg*.5m/s + .02kg*.7m/s = .03kg m/s + .014 kg m/s = .044
The total momentum of the system is not conserved from before the collision to after the collision.
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• What would the marble velocity have to be in order to exactly conserve momentum, assuming the steel ball's velocities to be accurate?
answer/question/discussion: ->->->->->->->->->->->-> :
.048 kg m/s = .06kg*.5m/s + .02kg*v2’
.018 kg m/s = .02 kg * v2’
V2’ = .9 m/s = 90 cm/s
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15 minutes
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