Assignment 1-11-08 2

course Mth 163

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Assignment 1-11-08

course Mth 163

end program???W??s?????????assignment #001

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qa prelim

????O???R????

assignment #002

002. Describing Graphs

qa initial problems

01-11-2008

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22:59:11

`q001. You will frequently need to describe the graphs you

have constructed in this course. This exercise is designed

to get you used to some of the terminology we use to

describe graphs. Please complete this exercise and email

your work to the instructor. Note that you should do these

graphs on paper without using a calculator. None of the

arithmetic involved here should require a calculator, and

you should not require the graphing capabilities of your

calculator to answer these questions.

Problem 1. We make a table for y = 2x + 7 as follows: We

construct two columns, and label the first column 'x' and

the second 'y'. Put the numbers -3, -2, -1, -, 1, 2, 3 in

the 'x' column. We substitute -3 into the expression and get

y = 2(-3) + 7 = 1. We substitute -2 and get y = 2(-2) + 7 =

3. Substituting the remaining numbers we get y values 5, 7,

9, 11 and 13. These numbers go into the second column, each

next to the x value from which it was obtained. We then

graph these points on a set of x-y coordinate axes. Noting

that these points lie on a straight line, we then construct

the line through the points.

Now make a table for and graph the function y = 3x - 4.

Identify the intercepts of the graph, i.e., the points where

the graph goes through the x and the y axes.

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RESPONSE -->

The point crosses the x axes at (1,0) and the y axes at (0,-

4).

confidence assessment: 2

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23:06:31

The graph goes through the x axis when y = 0 and through the

y axis when x = 0.

The x-intercept is therefore when 0 = 3x - 4, so 4 = 3x and

x = 4/3.

The y-intercept is when y = 3 * 0 - 4 = -4. Thus the x

intercept is at (4/3, 0) and the y intercept is at (0, -4).

Your graph should confirm this.

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RESPONSE -->

OK

$$$$$I see where the number goes into a fraction. It

happened from where the 3 was multiplied by the 0.$$$$$

self critique assessment: 2

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23:07:39

`q002. Does the steepness of the graph in the preceding

exercise (of the function y = 3x - 4) change? If so describe

how it changes.

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RESPONSE -->

Yes. It goes over to the right a little and makes the rest

of the graph steep.

confidence assessment: 2

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23:07:53

The graph forms a straight line with no change in steepness.

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RESPONSE -->

Yes

$$$$$If the numbers were different the line would be steeper

but where there was no change you can see the straight

line.$$$$$

self critique assessment: 2

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23:08:16

`q003. What is the slope of the graph of the preceding two

exercises (the function ia y = 3x - 4;slope is rise / run

between two points of the graph)?

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RESPONSE -->

Yes

$$$$$The rise/run is (4,1). You can see it as you look at

the graph from left to right.$$$$$

confidence assessment: 2

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23:09:55

Between any two points of the graph rise / run = 3.

For example, when x = 2 we have y = 3 * 2 - 4 = 2 and when x

= 8 we have y = 3 * 8 - 4 = 20. Between these points the

rise is 20 - 2 = 18 and the run is 8 - 2 = 6 so the slope is

rise / run = 18 / 6 = 3.

Note that 3 is the coefficient of x in y = 3x - 4.

Note the following for reference in subsequent problems: The

graph of this function is a straight line. The graph

increases as we move from left to right. We therefore say

that the graph is increasing, and that it is increasing at

constant rate because the steepness of a straight line

doesn't change.

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RESPONSE -->

Yes

$$$$$I see how the slope was determended by subtracting 20-

2=18. I don't understand where the 8-2=6 comes in to get the

slope of 3.$$$$$

When x = 2, y = 2 and when x = 8, y = 20.

Between these two graph points x changes from 2 to 8, which is a change of 8 - 2 = 6, and y changes from 2 to 20, which is a change of 20 - 2 = 18.

self critique assessment: 2

Your answer did not include enough detail for me to tell

that you understand.

Your self-critique should be detailed and demonstrate your

understanding of the given solution.

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23:13:25

`q004. Make a table of y vs. x for y = x^2. Graph y = x^2

between x = 0 and x = 3.

Would you say that the graph is increasing or decreasing?

Does the steepness of the graph change and if so, how?

Would you say that the graph is increasing at an increasing

rate, increasing at a constant rate, increasing at a

decreasing rate, decreasing at an decreasing rate,

decreasing at a constant rate, or decreasing at a decreasing

rate?

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RESPONSE -->

Increasing.

No.

Increasing at an increasing rate.

confidence assessment: 2

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23:15:06

`q005. Make a table of y vs. x for y = x^2. Graph y = x^2

between x = -3 and x = 0.

Would you say that the graph is increasing or decreasing?

Does the steepness of the graph change and if so, how?

Would you say that the graph is increasing at an increasing

rate, increasing at a constant rate, increasing at a

decreasing rate, decreasing at an decreasing rate,

decreasing at a constant rate, or decreasing at a decreasing

rate?

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RESPONSE -->

At an increasing it rate the numbers change the same

throughout the problem. At a constant rate it stays the same

as we move from left to right.

confidence assessment: 2

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23:15:45

From left to right the graph is decreasing (points (-3,9), (-

2,4), (-1,1), (0,0) show y values 9, 4, 1, 0 as we move from

left to right ). The magnitudes of the changes in x from 9

to 4 to 1 to 0 decrease, so the steepness is decreasing.

Thus the graph is decreasing, but more and more slowly. We

therefore say that the graph is decreasing at a decreasing

rate.

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RESPONSE -->

A rate of 3

$$$$$I see where the graph is decreasing in the y axes from

9,4,2,and 0. I don't understand what the magnitude has to do

with it. I can see the graph decreasing as you look at

it.$$$$$

The changes in y values from 9 to 4 to 1 to 0 are -5, -3 and -1.

In a sense -5 is a bigger change than -3, which is a bigger change than -1.

However since it -1 lies to the right of -3 on the number line, -1 is greater than -3, which is greater that -5, which confuses the idea of 'bigness'.

So the question of whether -5 is bigger than -3 migth not be determined by whether -5 is greater than -3, but by which magnitude is greater.

The magnitude of a number is its absolute value. So the magnitude of -5 is | -5 | = 5, and the magnitude of -3 is | -3 | = 3.

Related idea:

A series of negative numbers which progressively approach zero are increasing. Quantities which approach zero are generally thought of as getting 'smaller'. So these numbers are in this sense getting smaller while they are increasing.

Generally if a number has a large magnitude--i.e., a large absolute value--it can be thought of as being 'big', whether it is a 'big' positive number or a 'big' negative number, it's the magnitude that determines what we usually think of a size.

The words 'big' and 'small' do not have a general mathematical definition. We use the words 'greater' and 'lesser' to indicate position on the number line (the greater number lies to the right of the lesser). We use the magnitude of the number (its absolute value) when we want to refer to its size.

With respect to numbers, the words 'greater' and 'lesser', and the word 'magnitude', have well-defined mathematical meaning.

self critique assessment: 2

&#

Your response did not agree with the given solution in all

details, and you should therefore have addressed the

discrepancy with a full self-critique, detailing the

discrepancy and demonstrating exactly what you do and do not

understand about the given solution, and if necessary asking

specific questions (to which I will respond).

&#

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23:20:45

`q006. Make a table of y vs. x for y = `sqrt(x). [note: `sqrt

(x) means 'the square root of x']. Graph y = `sqrt(x)

between x = 0 and x = 3.

Would you say that the graph is increasing or decreasing?

Does the steepness of the graph change and if so, how?

Would you say that the graph is increasing at an increasing

rate, increasing at a constant rate, increasing at a

decreasing rate, decreasing at an decreasing rate,

decreasing at a constant rate, or decreasing at a decreasing

rate?

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RESPONSE -->

Increasing.

Yes. By 1.7.

Increasing at an increasing rate.

confidence assessment: 2

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23:22:02

If you use x values 0, 1, 2, 3, 4 you will obtain graph

points (0,0), (1,1), (2,1.414), (3. 1.732), (4,2). The y

value changes by less and less for every succeeding x value.

Thus the steepness of the graph is decreasing.

The graph would be increasing at a decreasing rate.

If the graph respresents the profile of a hill, the hill

starts out very steep but gets easier and easier to climb.

You are still climbing but you go up by less with each step,

so the rate of increase is decreasing.

If your graph doesn't look like this then you probably are

not using a consistent scale for at least one of the axes.

If your graph isn't as desribed take another look at your

plot and make a note in your response indicating any

difficulties.

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RESPONSE -->

OK

$$$$$I see how the graph changes less and less as you look

at it. As you look at the numbers and points and the line it

is a visual aid to see how the graph changes.$$$$$

self critique assessment: 2

&#

This also requires a self-critique.

&#

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23:24:52

`q007. Make a table of y vs. x for y = 5 * 2^(-x). Graph y =

5 * 2^(-x) between x = 0 and x = 3.

Would you say that the graph is increasing or decreasing?

Does the steepness of the graph change and if so, how?

Would you say that the graph is increasing at an increasing

rate, increasing at a constant rate, increasing at a

decreasing rate, decreasing at an decreasing rate,

decreasing at a constant rate, or decreasing at a decreasing

rate?

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RESPONSE -->

Decreasing.

Yes. It slopes down.

Decreasing at a constant rate.

confidence assessment: 2

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23:27:37

** From basic algebra recall that a^(-b) = 1 / (a^b).

So, for example:

2^-2 = 1 / (2^2) = 1/4, so 5 * 2^-2 = 5 * 1/4 = 5/4.

5* 2^-3 = 5 * (1 / 2^3) = 5 * 1/8 = 5/8. Etc.

The decimal equivalents of the values for x = 0 to x = 3

will be 5, 2.5, 1.25, .625. These values decrease, but by

less and less each time.

The graph is therefore decreasing at a decreasing rate. **

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RESPONSE -->

OK

$$$$$I was some what confused when I looked at this one. I

wasn't sure what the deal was with all the fractions. I got

the decimal part right on one of them which was .625. The

rest I didn't get at all. I am not sure what I did. I

understood the part that the graph is decreasing at a

decreasing rate.$$$$$

Do you see how

a^(-b) = 1 / (a^b) leads to

2^(-3) = 1 / (2^3)?

Do you see how

1 / (2^3) = 1/8?

Do you see how 1/8 = .125?

If so, do you then see how

2^(-2) = 1 / (2^2) = 1/4 = .25 ,

how

2^(-4) = 1 / (2^4) = 1 / 16 = .0625

and how

2^(-1) = 1 / (2^1) = 1 / 2 = .5?

To find the values of 5 * 2^(-x) we of course multiply these values by 5.

If these calculations aren't perfectly clear to you, send me a copy of this problem with your solution and your comments, and insert additional comments marked with &&&&. I'll be glad to continue clarifying as long as you keep asking.

self critique assessment: 2

&#

You need a detailed self-critique here.

&#

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23:30:38

`q008. Suppose you stand still in front of a driveway. A car

starts out next to you and moves away from you, traveling

faster and faster.

If y represents the distance from you to the car and t

represents the time in seconds since the car started out,

would a graph of y vs. t be increasing or decreasing?

Would you say that the graph is increasing at an increasing

rate, increasing at a constant rate, increasing at a

decreasing rate, decreasing at an decreasing rate,

decreasing at a constant rate, or decreasing at a decreasing

rate?

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RESPONSE -->

Increasing.

Increasing at an increasing rate.

confidence assessment: 2

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23:31:17

** The speed of the car increases so it goes further each

second. On a graph of distance vs. clock time there would be

a greater change in distance with each second, which would

cause a greater slope with each subsequent second. The graph

would therefore be increasing at an increasing rate. **

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RESPONSE -->

OK

$$$$$The faster the car goes the more seconds that goes by.

The longer the car runs the more it is going. It is always

increasing with the seconds and the speed that it is

going.$$$$$

self critique assessment: 2

.................................................""

Your answers demonstrate that you understand some of these

concepts, but you haven't included enough justification in

your answers to demonstrate what you do and do not

understand, and you did not self-critique in the prescribed

manner.

&#Please respond with a copy of this document, including my

comments. Insert your revisions and/or questions and/or self-

critiques, as appropriate, and mark them with $$$$. &#

"

You asked excellent questions. See my answers and if you have additional questions on anything, send a copy of the appropriate material with your additional comments indicated by &&&&.