course Mth 163 HЯD̏θ䙣dassignment #009
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19:46:14 `q001. Note that this assignment has 2 questions For the function y = 1.1 x + .8, what are the coordinates of the x = x1 point, in terms of the symbol x1? What are the coordinates of the x = x2 point, in terms of the symbol x2? What therefore is the rise between these two points, and what is the run? What is the average slope of the graph between these two points? Be sure to simplify your result.
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RESPONSE --> The coordinates of x=x1 points are x1, 1.1, x1+ .8. The coordinates of x=x2 points are x2, 1.1, x2 + .8. The rise of the two points are: (1.1 x2 + .8) - (1.1 x1 + .8) = 1.1 x2 + .8 - 1.1 x1 - .8 = 1.1 x2 -1.1 x1. The run of the two points are: x2 - x1. The slope is: (1.1 x2 - 1.1 x1) / (x2 - x1) = 1.1 (x2 - x1) / (x2-x1) = 1.1 confidence assessment: 2
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19:48:07 In terms of the symbol x1 the coordinates of the x = x1 point are ( x1, 1.1 x1 + .8) and the coordinates of the x = x2 point are ( x2, 1.1 x2 + .8). The rise between the two points is therefore rise = (1.1 x2 + .8) - (1.1 x1 + .8) = 1.1 x2 + .8 - 1.1 x1 - .8 = 1.1 x2 - 1.1 x1. The run is run = x2 - x1. The slope is therefore (1.1 x2 - 1.1 x1) / (x2 - x1) = 1.1 (x2 - x1) / (x2 - x1) = 1.1.
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RESPONSE --> I see how the coordinates of the points are found. The rise and run seem easy to find. It just a matter of putting everything in order. Finding the slope is also another thing that seems easy enough to find. You just need to place the rise over the run and divide it to find the slope. self critique assessment: 3
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19:57:29 `q002. For the function y = 3.4 x + 7, what are the coordinates of the x = x1 point, in terms of the symbol x1? What are the coordinates of the x = x2 point, in terms of the symbol x2? What therefore is the rise between these two points, and what is the run? What is the average slope of the graph between these two points? Be sure to simplify your result.
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RESPONSE --> The coordinate points of x=x1 are x1, 3.4 x1 + 7 and the corrdinante points of x=x2 are x2, 3.4 x2 + 7. The rise of the two points are: (3.4 x2 +7) - (3.4 x1 + 7) = 3.4 x2 + 7 - 3.4 x1 - 7 = 3.4 x2 - 3.4 x1. The run of the two points are: x2 - x1 The slope is: (3.4 x2 - 3.4 x1) / (x2 - x1) = 3.4 (x2 - x1) / (x2- x1) = 3.4 confidence assessment: 2
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19:58:22 In terms of the symbol x1 the coordinates of the x = x1 point are ( x1, 3.4 x1 + 7) and the coordinates of the x = x2 point are ( x2, 3.4 x2 + 7). The rise between the two points is therefore rise = (3.4 x2 + 7) - (3.4 x1 + 7) = 3.4 x2 + 7 - 3.4 x1 - 7 = 3.4 x2 - 3.4 x1. The run is run = x2 - x1. The slope is therefore (3.4 x2 - 3.4 x1) / (x2 - x1) = 3.4 (x2 - x1) / (x2 - x1) = 3.4.
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RESPONSE --> I understand how you find the coordinate points. I also see how you find the rise, run, and slope. It is just a matter of getting everything in the place that they belong. self critique assessment: 3
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