#$&* course mth173 If a sand pile 2.7 meters high has a mass of 8660.521 kg, then what would we expect to be the mass of a geometrically similar sand pile 6.7 meters high? 8660.521/2.7 = x / 6.7 8660.521/2.7*6.7 = roughly 21,490.9kg. This is about 3207.6 kg/m v = k y v = 3207.6y If there are 1.5309 billion grains of sand exposed on the surface of the first sand pile, how many grains of sand we expect to be exposed on the surface of the second? Using the derivative from the class notes 5 or 6, y` = .006x^2, we can plug in the 1,530,900,000 for x to find how many grains of sand are in the second pile.