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course mth173
If a sand pile 5 meters high has a mass of 236000 kg, then what would we expect to be the mass of a geometrically similar sand pile 15 meters high?v = kx
236,000 = 5k
236000/5 = 47,200
v = 47200(15)
v = 708000 kg
Using the differential estimate the mass of sand required to increase the height of the pile from 5 meters to 5.02 meters.
In accordance with class notes 6, we can use the derivative .006x^2 to find the rate at which the change is happening.
.006(25) = .15 tbsp/meter
We can then say that the slope will be equal to 1.15 at this point in time.
We can multiply the slope by the run, which is the .02 change in meters, to find the rise, which will be the amount of sand required to make the change.
1.15 * .02 = .023 tbsp of sand will be required to make the diameter change from 5 to 5.02 meters."
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As on the preceding, you need to use the proportionalities appropriate to the situation.
Please review the appropriate, reword this problem, and resubmit.
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