Open Query 5-2

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course MTH 151

Time of submission: 8:08 PM, 16 April 2012

If your solution to stated problem does not match the given solution, you should self-critique per instructions athttp://vhcc2.vhcc.edu/dsmith/geninfo/labrynth_created_fall_05/levl1_22/levl2_81/file3_259.htm

Your solution, attempt at solution. If you are unable to attempt a solution, give a phrase-by-phrase interpretation of the problem along with a statement of what you do or do not understand about it. This response should be given, based on the work you did in completing the assignment, before you look at the given solution.

023. `query 23

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Question: `q5.1.18 List all the factors of 172.

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Your solution:

- 2*86 = 172

- 3 (remainder, no factor)

- 4*43 = 172

- 5 (remainder, no factor)

- 6 (remainder, no factor)

- 7(remainder, no factor)

- 8(remainder, no factor)

- 9 (remainder, no factor)

- 10 (remainder, no factor)

- 11 (remainder, no factor)

- 12(remainder, no factor)

13 (NF)

- 14(NF)

- 15 (NF)

- 16(NF)

- 43…

Therefore, all factors of 172 are (2 and 86), (4 and 43) and of course the 1:1 ratio, (1 and 172)

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Given Solution:

`a** If the number isn't too big we can simply start dividing by primes, beginning with the smallest:

If we divide 172 by 2 we get 86, so 2 and 86 are factors.

If we divide 172 by 3 we get 57 with a remainder so 3 isn't a factor.

If we divide 172 by 4 we get 43, so 4 and 43 are factors.

If we divide 172 by 5 we get 34 with a remainder so 5 isn't a factor.

If we divide 172 by 6 we get 28 with remainder so 6 isn't a factor.

If we divide 172 by 7 we get 24 with a remainder so 7 isn't a factor.

If we divide 172 by 8 we get 21 with remainder so 8 isn't a factor.

If we divide 172 by 9 we get 19 with a remainder so 9 isn't a factor.

If we divide 172 by 10 we get 17 with a remainder so 10 isn't a factor.

If we divide 172 by 11 we get 15 with a remainder so 11 isn't a factor.

If we divide 172 by 12 we get 14 with a remainder so 12 isn't a factor.

If we divide 172 by 13 we get 13 with a remainder so 13 isn't a factor.

If we were to divide 172 by any number greater than 13 the result would be less than 13. We've already divided by every whole number less than 13 so we aren't going to find anything new by dividing by numbers greater than 13.

Our factors are 2, 86, 4 and 43, as well as 1 and the number 172 itself.

A method which is often quicker if the prime factorization contains a large number of factors is to list every prime factor, every product of two prime factors, every product of three prime factors, etc.:

From the Prime Factorization 172 = 2 * 2 * 43 you find that the factors include:

Each prime factor: 2 and 43

Each product of two prime factors: 2 * 2 = 4 and 2 * 43 = 86

The number itself and 1: 1 and 172.

This method is quicker and more reliable than dividing by every possible number (what would you do with 5,668,725, for example?). **

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Self-critique (if necessary): Can one generally assume that, when determining factors, when one reaches a divisor whose quotient, as the whole number, is equal to the divisor, we’ve reached the “multiplicative climax?”

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Self-critique Rating:

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I really like the way you put that.

That is so.

You don't have to understand, or even read what follows but your description deserves further comment:

A quick proof that it's so:

If the whole-number part of n / p is equal to p, then n / p is less than p + 1 (e.g., 29 / 5 = 5.8, which is less than 5 + 1, which would be 6).

So the condition you state can be written as

n / p < p + 1.

A little algebra (specifically, multiplying both sides by p and then dividing both sides by p + 1) tells us that this is equivalent to

n / (p + 1) < p.

This tells us that if we divide by the next-higher number the result will be less than the divisor, which is the condition that characterizes the 'multiplicative climax', as you so nicely describe it.

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Question: `q5.1.21 divisibility of 25025 by various factors.

Explain how each divisibility test works for the number 25025.

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Your solution:

- When given a number like 25,025 you use the sum of its digits (2+5+0+2+5 = 14) and thereby turns it to a smaller number in which to work with. From 14, you test to see what divisors can successfully “go into” 14.

- The numbers 2 and 7 are examples. When you find that the divisor you pick, being a natural/whole number, you find what a larger number is divisible by.

confidence rating #$&*:

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Given Solution:

`a**

25025 is not divisible by 2 because it doesn't end in an even number.

25025 isn't divisible by 3 because the sum 2 + 5 + 0 + 2 + 5 = 14 of its digits is not divisible by 3.

25025 isn't divisible by 4 because its last two digits do not form a number divisible by 4.

25025 is divisible by 5 because its last digit is 5.

25025 isn't divisible by 6 because it isn't divisible by 2 and 3.

25025 isn't divisible by 8 because its last three digits do not form a number divisible by 8.

25025 isn't divisible by 9 because the sum 2 + 5 + 0 + 2 + 5 = 14 of its digits is not divisible by 9.

25025 isn't divisible by 12 because it isn't divisible by both 3 and 4.**

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Self-critique (if necessary):

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Self-critique Rating:

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Question: `q5.1.33 What is the prime factorization of 360 and how did you get it?

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Your solution:

- Start with the smallest possible option other than 1; 2.

- 360 /2 = 180.

- 180/2 = 90.

- 90/2 = 45.

- 45/2 = 22.5. ***Now that we see the whole pattern breaks, it’s time to move onto a larger number to divide by, 3.

- 45/3 = 15.

- 15 / 3 = 5.

To get the prime factorization, simply multiply 2 * 2 * 2 * 3 * 3 * 5 = 360

confidence rating #$&*:

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Given Solution:

`a** We can follow the simplest method, dividing successively by the smallest possible prime:

360 / 2 = 180, so 2 is a prime factor.

180 / 2 = 90, so 2 is again a factor.

90 / 2 = 45, so 2 is again a factor.

45 can't be divided by 2 so we note that 2 occurs 3 times as a factor and try division by 3:

45 / 3 = 15, so 3 is a factor.

15 / 3 = 5, so 3 is again a factor.

5 is itself prime.

It follows that 360 = 2 * 2 * 2 * 3 * 3 * 5, as can be easily checked by multiplication.

Thus the prime factorization is 360 = 2^3 * 3^2 * 5. **

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Self-critique (if necessary):

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Self-critique Rating:

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Question: `q5.1.60 number of divisors of 2^4*3^4*5^2

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Your solution:

- Look at the exponents, separate them, add one to each, and take the product.

- 4, 4, 2.

(4+1) * (4 +1) * (2+1) = 5 * 5 * 3 = 75.

Thus, there are 75 possible factors

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confidence rating #$&*:

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Given Solution:

`a** The powers are 4, 4 and 2.

The number of possible factors is therefore (4 + 1) * (4 + 1) * (2 + 1) = 5 * 5 * 3 = 75. **

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Self-critique (if necessary):

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Self-critique Rating:

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Question: `qquery 5.1.80 is 2*3*...*13+1 prime?

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Your solution:

- 2*3*5*7*11*13 +1 = 30031

- No prime numbers to equal….Not prime.

confidence rating #$&*:

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Given Solution:

`a** To test for primeness you have to divide the number by every prime up to and including its square root. Having done so, you will either find that one of these primes does divide the number, or you will find that none does. Either way you will be able to answer the question.

The number we need to test is 2 * 3 * 5 * 7 * 11 * 13 + 1 = 30031. Note that even though this is a pretty good-sized number it's not that big a task to divide by all primes up to the square root. The square root of 30031 is less than 174 so we only have to divide by primes less than 174, and there aren't all that many of them. Besides if one of the numbers 'works' we can stop.

In fact 30,031 is not prime. Dividing by the prime numbers 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, all lead to fractional results. But on the next prime 59 we hit paydirt because 30,031 = 59 * 509 so 30031 isn't prime. **

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Self-critique (if necessary):

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Self-critique rating:

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Question: `qquery 5.1.80 is 2*3*...*13+1 prime?

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Your solution:

- 2*3*5*7*11*13 +1 = 30031

- No prime numbers to equal….Not prime.

confidence rating #$&*:

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Given Solution:

`a** To test for primeness you have to divide the number by every prime up to and including its square root. Having done so, you will either find that one of these primes does divide the number, or you will find that none does. Either way you will be able to answer the question.

The number we need to test is 2 * 3 * 5 * 7 * 11 * 13 + 1 = 30031. Note that even though this is a pretty good-sized number it's not that big a task to divide by all primes up to the square root. The square root of 30031 is less than 174 so we only have to divide by primes less than 174, and there aren't all that many of them. Besides if one of the numbers 'works' we can stop.

In fact 30,031 is not prime. Dividing by the prime numbers 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, all lead to fractional results. But on the next prime 59 we hit paydirt because 30,031 = 59 * 509 so 30031 isn't prime. **

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Self-critique (if necessary):

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Self-critique rating:

#*&!

@&

Very good.

See my note on your question, which incidentally you posed very capably.

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