Query 5

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course 272

10/20 9:50pm

Your solution, attempt at solution: If you are unable to attempt a solution, give a phrase-by-phrase interpretation of the problem along with a statement of what you do or do not understand about it. This response should be given, based on the work you did in completing the assignment, before you look at the given solution.

005. `query 5

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Question: `q 5.1.5 (previously 5.1.12) integrate 3 t^4 dt and check by differentiation

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Your solution:

Applying the constant rule: 3(x^4 dx)

Applying the simple power rule: 3 (x^5/5)

Simplified answer: 3(t^5/5) + C

Check with differentiation: 3/5 * 5 t^4 = 3t^4

confidence rating #$&*: 3

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Given Solution:

`a An antiderivative of the power function t^4 is one power higher so it will be a multiple of t^5. Since the derivative of t^5 is 5 t^4 an antiderivative of t^4 is be t^5 / 5. By the constant rule the antiderivative of 3 t^4 is therefore 3 * t^5 / 5. Adding the arbitrary integration constant we end up with general antiderivative3 t^5 / 5 + c.

The derivative of 3/5 t^5 is 3/5 * 5 t^4 = 3 t^4), verifying our antiderivative. **

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Self-critique (if necessary): ok

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Self-critique Rating: 3

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Question: `q 5.1.7 (previously 5.1.20 (was 5.1.18)) integrate v^-.5 dv and check by differentiation

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Your solution:

v^-.5 dv =

Simplie power rule: v^.5 /.5 = 2v^.5

Add the constant: 2v^.5 + C

Check by differentiation: 2v^.5 = 2*1/2 *.5v^.5 = v^-.5

confidence rating #$&*: 3

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Given Solution:

`a An antiderivative of this power function is a constant multiple of the power function which is one power higher. The power of the present function is -.5 or -1/2; one power higher is +.5 or 1/2. So you will have a multiple of v^.5. Since the derivative of v^.5 is .5 v^-.5 an antiderivative will be v^.5 / .5 = v^(1/2) / (1/2) = 2 v^(1/2). Adding the arbitrary integration constant we end up with general antiderivative 2 v^(1/2) + c.

The derivative of 2 v^(1/2) is 2 * (1/2) v^(-1/2) = v^(-1/2), verifying our antiderivative. **

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Self-critique (if necessary): ok

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Self-critique Rating: 3

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Question: `q Add comments on any surprises or insights you experienced as a result of this assignment.

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Self-critique (if necessary):

So far I am comfortable using the basic integration rules to rewrite, integrate and simplify to find the antiderivatives.

"

Self-critique (if necessary):

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Self-critique rating:

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Question: `q Add comments on any surprises or insights you experienced as a result of this assignment.

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Self-critique (if necessary):

So far I am comfortable using the basic integration rules to rewrite, integrate and simplify to find the antiderivatives.

"

Self-critique (if necessary):

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Self-critique rating:

#*&!

&#Good responses. Let me know if you have questions. &#