Query 26

#$&*

course 272

11/30 7:45pm

If your solution to a stated problem does not match the given solution, you should self-critique per instructions at

http://vhcc2.vhcc.edu/dsmith/geninfo/labrynth_created_fall_05/levl1_22/levl2_81/file3_259.htm.

Your solution, attempt at solution: If you are unable to attempt a solution, give a phrase-by-phrase interpretation of the problem along with a statement of what you do or do not understand about it. This response should be given, based on the work you did in completing the assignment, before you look at the given solution.

026.

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Question: `qQuery problem 7.3.38 level curves of z = e^(xy), c = 1, 2, 3, 4, 1/2, 1/3, 1/4.

z = e^(xy)

c = e^(xy)

ln(c) = ln (e^(xy)) = xy

ln(c) / x = y

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Your solution:

C Y = ln(c)/ x Curve passes through points: asymtotes

1 Y = ln(1)/ x = 0 Level curve is x axis y = 0

2 Y = ln(2)/ x = .7/x (1, .7), (-1, -.7) x and y axis

3 Y = ln(3)/ x = 1.1/x (2, 1.1), (-2, -1.1) x and y axis

4 Y = ln(4)/ x = 1.4/x (4, 1.4), (-4, -1.4) x and y axis

½ Y = ln(1/2)/ x = -.7/x (-1/2, .7), (-1/2, -.7) x and y axis

1/3 Y = ln(1/3)/ x = -1.1/x (-1/3, 1.1), (-1/3, -1.1) x and y axis

¼ Y = ln(1/4)/ x = -1.4/x (-1/4, 1.4), (-1/4, -1.4) x and y axis

confidence rating #$&*: 3

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Given Solution:

`a The z = c level curve of e^(xy) occurs when e^(xy) = c.

We solve e^(xy) = c for y in terms of x. We first take the natural log of both sides:

ln(e^(xy)) = ln(c), or

xy = ln(c). We then divide both sides by x:

y = ln(c) / x.

For c = 1 we get y = ln(1) / x = 0 / x = 0. Thus the c = 1 level curve is the x axis y = 0.

For c = 2 we get y = ln(2) / x = .7 / x, approximately. This curve passes through the points (1,.7) and (-1, -.7), and is asymptotic to both the x and y axes.

For c = 3 we get y = ln(3) / x = 1.1 / x, approximately. This curve passes through the points (1,1.1) and (-1, -1.1), and is asymptotic to both the x and y axes.

For c = 4 we get y = ln(4) / x = 1.39 / x, approximately. This curve passes through the points (1,1.39) and (-1, -1.39), and is asymptotic to both the x and y axes.

For c = 1/2 we get y = ln(1/2) / x = -.7 / x, approximately. This curve passes through the points (-1,.7) and -1, -.7), and is asymptotic to both the x and y axes.

For c = 1/3 we get y = ln(1/3) / x = -1.1 / x, approximately. This curve passes through the points (-1,1.1) and -1, -1.1), and is asymptotic to both the x and y axes.

For c = 1/4 we get y = ln(1/4) / x = -1.39 / x, approximately. This curve passes through the points (-1,1.39) and -1, -1.39), and is asymptotic to both the x and y axes.

The c = 2, 3, 4 level curves form similar hyperbolas in the first and third quadrant which progressively 'bunch up' closer and closer together. Similar behavior is observed for the c = 1/2, 1/3, 1/4 hyperbolas, which occur in the second and fourth quadrants.

STUDENT COMMENT

I had a little bit of trouble applying my graphing here given dimension, but clear pertaining to concept, making a bit more progress. 
INSTRUCTOR RESPONSE

You should be very familiar with the graph of y = 1 / x. Focus on the point (1, 1) and the fact that the graph in the right half-plane has asymptotes with the positive y and positive x axes.
If you multiply this function by ln(c) the point becomes (1, ln(c)). For c = 1, 2, 3, 4 the points rise higher and higher, but with less space between successive points. The level curves pass through these points, still with asymptotes at the x and y axes. Each curve is a bit 'higher' than the preceding.

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Self-critique (if necessary): ok

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Self-critique Rating: 3

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Question: `qQuery problem 7.3.46 queuing model W(x,y) = 1 / (x-y), y < x (y = ave arrival rate, x = aver service rate).

What are the values of W at (15, 10), (12, 9), (12, 6) and (4,2)?

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Your solution:

W(x,y) = 1 / (x-y)

W(15,10) = 1 / (15-10) = 1/5

W(12,9) = 1 / (12-9) = 1/3

W(12,6) = 1 / (12-6) = 1/6

W(4,2) = 1 / (4-2) = 1/2

confidence rating #$&*: 3

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Given Solution:

`a 1/5, 1/3, 1/6, 1/2

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Self-critique (if necessary):

ok

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Self-critique Rating: 3

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Question: `qYou may take extra time with the following: What is the nature of the worst combination of x and y, and why is this bad--both in terms of the behavior of the function and in terms of the real-world situation?

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Your solution:

I know the worst scenario would be when the arrival rate (y) is almost as long as the service rate (x).

confidence rating #$&*:

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Given Solution:

`aGood answer by student:

x=service, y=arrival rate

therefore the worst senerio would be when the arrival rate was almost as long as the service rate...its worse to have a customer waiting a long time than having a customer being served for a long time

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Self-critique (if necessary):

Ah ha, I understand this example and the relationship in this scenario.

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Self-critique Rating: 3

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Question: `qQuery Add comments on any surprises or insights you experienced as a result of this assignment.

I’m comfortable with the functions with several variables so far.

"

Self-critique (if necessary):

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Self-critique rating:

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Question: `qQuery Add comments on any surprises or insights you experienced as a result of this assignment.

I’m comfortable with the functions with several variables so far.

"

Self-critique (if necessary):

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Self-critique rating:

#*&!

&#Your work looks good. Let me know if you have any questions. &#