course mth 151 {oS[ܼassignment #003
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14:13:31 Query 2.3.15 (Y ^ Z')U X, univ={a,..g}, X={a,c,e,g}, Y = {a,b,c}, Z = {b, ..., f} What is the set (Y ^ Z')U X?
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RESPONSE --> Z' IS {a,g} Y^Z' IS {a} because a is the only common element. So (Y^Z')UX = {a,c,e,g} the set of all elements that lie in at least one of the sets confidence assessment: 2
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14:14:17 **Z' = {a,g}, the set of all elements of the universal set not in Z. Y ^ Z' = {a}, since a is the only element common to both Y and Z'. So (Y ^ Z') U X = {a, c, e, g}, the set of all elements which lie in at least one of the sets (Y ^ Z') U X. **
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RESPONSE --> we wanted the set of all elements which lie in at least one of the sets. self critique assessment: 2
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14:17:47 Give the intersection of the two sets Y and Z'
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RESPONSE --> Y = {a,b,c} Z' = {a,g} set of elements common to both Y and Z' is {a} confidence assessment: 2
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14:18:23 **Z' = {a,g}, the set of all elements of the universal set not in Z. Y ^ Z' = {a}, since a is the only element common to both Y and Z'.**
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RESPONSE --> Z' is the set of all elements of the universal set no in Z self critique assessment: 2
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14:19:25 Query 2.3.30 describe in words (A ^ B' ) U (B ^ A')
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RESPONSE --> All elements that are in A but not in B, and all elements that are in B but not in A. confidence assessment: 2
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14:20:20 ** a description, not using a lot of set-theoretic terms, of (A ^ B' ) U (B ^ A') would be, all the elements that are in A and not in B, or that are not in A and are in B Or you might want to say something like 'elements which are in A but not B OR which are in B but not A'. STUDENT SOLUTION WITH INSTRUCTOR COMMENT:everything that is in set A and not in set B or everything that is in set B and is not in set A. INSTRUCTOR COMMENT: I'd avoid the use of 'everything' unless the word is necessary to the description. Otherwise it's likely to be misleading. **
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RESPONSE --> Ok I think I forgot my ' sign on my A', but I had the right idea. self critique assessment: 2
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14:25:45 2.3.51 always or not always true: n(A U B) = n(A)+n(B)
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RESPONSE --> it would be always true because n(A) is all elements in A and n(B) is all elements in B and when you add them together you get all elements that are in A and B, which is what the U of A and B is. confidence assessment: 2
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14:26:57 ** This conclusion is contradicted by many examples, including the one of the dark-haired and bright-eyed people in the q_a_. Basically n(A U B) isn't equal to n(A) + n(B) if there are some elements which are in both sets--i.e., in the intersection. } MORE DETAIL: The statement can be either true or false, depending on the sets A and B; it is not always true. The statement n(A U B) = n(A)+n(B) means that the number of elements in A U B is equal to the sum of the number of elements in A and the number of elements in B. The statement would be true for A = { c, f } and B = { a, g, h} because A U B would be { a, c, f, g, h} so n(A U B) = 5, and n(A) + n(B) = 2 + 3 = 5. The statement would not be true for A = { c, f, g } and B = { a, g, h} because A U B would be the same as before so n(AUB) = 5, while n(A) + n(B) = 3 + 3 = 6. The precise condition for which the statement is true is that A and B have nothing in common. In that case n(A U B) = n(A) + n(B). A more precise mathematical way to state this is to say that n(A U B) = n(A) + n(B) if and only if the intersection A ^ B of the two sets is empty. **
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RESPONSE --> Ok now that is just to tricky. But I do see what you mean self critique assessment: 2
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14:35:13 Query 2.3.60 X = {1,3,5}, Y = {1,2,3}. Find (X ^ Y)' and X' U Y'.
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RESPONSE --> (X^Y)' is all elements that is not in the ^ of X and Y, the intersection of X and Y is {1,3} so that leaves {2,5} being the intersection of (X^Y)' X' is everything not in X which is 5 and everything that is not in Y is 2 so X' U Y' = {2,5) confidence assessment: 2
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14:37:00 ** X ^ Y = {1,3} so (X ^ Y) ' = {1,3}' = {2, 4, 5}. (X ' U Y ' ) = {2, 4} U {4, 5} = {2, 4, 5} The two resulting sets are equal so a reasonable conjecture would be that (X ^ Y)' = X' U Y'. **
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RESPONSE --> Ok, I see what I did, I left the 4 out for the Universe. self critique assessment: 2
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14:44:06 2.3.72 A = {3,6,9,12}, B = {6,8}.
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RESPONSE --> AxB= {(3,6),(3,8),(6,6),(6,8),(9,6),(9,8),(12,6),(12,8)} BxA= {(6,3),(8,3),(6,6),(8,6),(6,9),(8,9),(6,12),(8,12)} confidence assessment: 2
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14:45:01 ** (A X B) = {(3,6),(3,8),(6,6),(6,8),(9,6),(9,8),(12,6), (12,8)} (B X A) = (6,3),(6,6),(6,9),(6,12),(8,3),(8,6),(8,9),(8,12)} How is n(A x B) related to n(A) and n(B)? n(S) stands for the number of elements in the set S, i.e., its cardinality. n(A x B) = n(A) * n(B) **
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RESPONSE --> n(S) stands for the number of elements in the set S self critique assessment: 2
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14:46:51 2.3.84 Shade A U B
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RESPONSE --> You would shade all elements in A and all elements in B which is section 2,3, and 4 in our book confidence assessment: 2
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14:47:31 ** everything in A and everything in B would be shaded. The rest of the universal set (the region outside A and B but still in the rectangle) wouldn't be. **
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RESPONSE --> the region outside A and B but still in the rectangle would not be shaded. self critique assessment: 2
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14:50:43 Query 2.3.100 Shade (A' ^ B) ^ C
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RESPONSE --> You would shade all elements that is not in A but is in B and all of C. confidence assessment: 2
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14:51:40 ** you would have to shade every region that lies outside of A and also inside B and also inside C. This would be the single region in the overlap of B and C but not including any part of A. Another way to put it: the region common to B and C, but not including any of A **
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RESPONSE --> every region that lies outside of A and also inside B and also inside C. self critique assessment: 2
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14:53:06 Describe the shading of the set (A ^ B)' U C.
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RESPONSE --> You would shade the section that is not in A or B which is C and C again. confidence assessment: 2
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14:53:36 ** All of C would be shaded because we have a union with C, which will include all of C. Every region outside A ^ B would also be shaded. A ^ B is the 'overlap' region where A and B meet, and only this 'overlap' would not be part of (A ^ B) '. The 'large' parts of A and B, as well as everything outside of A and B, would therefore be shaded. Combining this with the shading of C the only the part of the diagram not shaded would be that part of the 'overlap' of A and B which is not part of C. **
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RESPONSE --> We have a union with C, which includes all of C self critique assessment: 2
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15:09:30 2.3.114 Largest area of A shaded (sets A,B,C). Write a description using A, B, C, subset, union, intersection symbols, ', - for the shaded region.
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RESPONSE --> The region in color is in set A and is not in B and is not in C so we get A^B'^C' confidence assessment: 2
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15:10:23 ** Student Answer and Instructor Response: (B'^C')^A Instructor Response: Good. Another alternative would be A - (B U C ), and others are mentioned below. COMMON ERROR: A ^ (B' U C') INSTRUCTOR COMMENT: This is close but A ^ (B' U C') would contain all of B ^ C, including a part that's not shaded. A ^ (B U C)' would be one correct answer. **
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RESPONSE --> (B^C')^A is another response self critique assessment: 2
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course mth 151
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14:13:31 Query 2.3.15 (Y ^ Z')U X, univ={a,..g}, X={a,c,e,g}, Y = {a,b,c}, Z = {b, ..., f} What is the set (Y ^ Z')U X?
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RESPONSE --> Z' IS {a,g} Y^Z' IS {a} because a is the only common element. So (Y^Z')UX = {a,c,e,g} the set of all elements that lie in at least one of the sets confidence assessment: 2
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14:14:17 **Z' = {a,g}, the set of all elements of the universal set not in Z. Y ^ Z' = {a}, since a is the only element common to both Y and Z'. So (Y ^ Z') U X = {a, c, e, g}, the set of all elements which lie in at least one of the sets (Y ^ Z') U X. **
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RESPONSE --> we wanted the set of all elements which lie in at least one of the sets. self critique assessment: 2
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14:17:47 Give the intersection of the two sets Y and Z'
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RESPONSE --> Y = {a,b,c} Z' = {a,g} set of elements common to both Y and Z' is {a} confidence assessment: 2
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14:18:23 **Z' = {a,g}, the set of all elements of the universal set not in Z. Y ^ Z' = {a}, since a is the only element common to both Y and Z'.**
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RESPONSE --> Z' is the set of all elements of the universal set no in Z self critique assessment: 2
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14:19:25 Query 2.3.30 describe in words (A ^ B' ) U (B ^ A')
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RESPONSE --> All elements that are in A but not in B, and all elements that are in B but not in A. confidence assessment: 2
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14:20:20 ** a description, not using a lot of set-theoretic terms, of (A ^ B' ) U (B ^ A') would be, all the elements that are in A and not in B, or that are not in A and are in B Or you might want to say something like 'elements which are in A but not B OR which are in B but not A'. STUDENT SOLUTION WITH INSTRUCTOR COMMENT:everything that is in set A and not in set B or everything that is in set B and is not in set A. INSTRUCTOR COMMENT: I'd avoid the use of 'everything' unless the word is necessary to the description. Otherwise it's likely to be misleading. **
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RESPONSE --> Ok I think I forgot my ' sign on my A', but I had the right idea. self critique assessment: 2
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14:25:45 2.3.51 always or not always true: n(A U B) = n(A)+n(B)
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RESPONSE --> it would be always true because n(A) is all elements in A and n(B) is all elements in B and when you add them together you get all elements that are in A and B, which is what the U of A and B is. confidence assessment: 2
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14:26:57 ** This conclusion is contradicted by many examples, including the one of the dark-haired and bright-eyed people in the q_a_. Basically n(A U B) isn't equal to n(A) + n(B) if there are some elements which are in both sets--i.e., in the intersection. } MORE DETAIL: The statement can be either true or false, depending on the sets A and B; it is not always true. The statement n(A U B) = n(A)+n(B) means that the number of elements in A U B is equal to the sum of the number of elements in A and the number of elements in B. The statement would be true for A = { c, f } and B = { a, g, h} because A U B would be { a, c, f, g, h} so n(A U B) = 5, and n(A) + n(B) = 2 + 3 = 5. The statement would not be true for A = { c, f, g } and B = { a, g, h} because A U B would be the same as before so n(AUB) = 5, while n(A) + n(B) = 3 + 3 = 6. The precise condition for which the statement is true is that A and B have nothing in common. In that case n(A U B) = n(A) + n(B). A more precise mathematical way to state this is to say that n(A U B) = n(A) + n(B) if and only if the intersection A ^ B of the two sets is empty. **
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RESPONSE --> Ok now that is just to tricky. But I do see what you mean self critique assessment: 2
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14:35:13 Query 2.3.60 X = {1,3,5}, Y = {1,2,3}. Find (X ^ Y)' and X' U Y'.
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RESPONSE --> (X^Y)' is all elements that is not in the ^ of X and Y, the intersection of X and Y is {1,3} so that leaves {2,5} being the intersection of (X^Y)' X' is everything not in X which is 5 and everything that is not in Y is 2 so X' U Y' = {2,5) confidence assessment: 2
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14:37:00 ** X ^ Y = {1,3} so (X ^ Y) ' = {1,3}' = {2, 4, 5}. (X ' U Y ' ) = {2, 4} U {4, 5} = {2, 4, 5} The two resulting sets are equal so a reasonable conjecture would be that (X ^ Y)' = X' U Y'. **
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RESPONSE --> Ok, I see what I did, I left the 4 out for the Universe. self critique assessment: 2
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14:44:06 2.3.72 A = {3,6,9,12}, B = {6,8}.
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RESPONSE --> AxB= {(3,6),(3,8),(6,6),(6,8),(9,6),(9,8),(12,6),(12,8)} BxA= {(6,3),(8,3),(6,6),(8,6),(6,9),(8,9),(6,12),(8,12)} confidence assessment: 2
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14:45:01 ** (A X B) = {(3,6),(3,8),(6,6),(6,8),(9,6),(9,8),(12,6), (12,8)} (B X A) = (6,3),(6,6),(6,9),(6,12),(8,3),(8,6),(8,9),(8,12)} How is n(A x B) related to n(A) and n(B)? n(S) stands for the number of elements in the set S, i.e., its cardinality. n(A x B) = n(A) * n(B) **
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RESPONSE --> n(S) stands for the number of elements in the set S self critique assessment: 2
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14:46:51 2.3.84 Shade A U B
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RESPONSE --> You would shade all elements in A and all elements in B which is section 2,3, and 4 in our book confidence assessment: 2
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14:47:31 ** everything in A and everything in B would be shaded. The rest of the universal set (the region outside A and B but still in the rectangle) wouldn't be. **
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RESPONSE --> the region outside A and B but still in the rectangle would not be shaded. self critique assessment: 2
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14:50:43 Query 2.3.100 Shade (A' ^ B) ^ C
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RESPONSE --> You would shade all elements that is not in A but is in B and all of C. confidence assessment: 2
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14:51:40 ** you would have to shade every region that lies outside of A and also inside B and also inside C. This would be the single region in the overlap of B and C but not including any part of A. Another way to put it: the region common to B and C, but not including any of A **
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RESPONSE --> every region that lies outside of A and also inside B and also inside C. self critique assessment: 2
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14:53:06 Describe the shading of the set (A ^ B)' U C.
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RESPONSE --> You would shade the section that is not in A or B which is C and C again. confidence assessment: 2
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14:53:36 ** All of C would be shaded because we have a union with C, which will include all of C. Every region outside A ^ B would also be shaded. A ^ B is the 'overlap' region where A and B meet, and only this 'overlap' would not be part of (A ^ B) '. The 'large' parts of A and B, as well as everything outside of A and B, would therefore be shaded. Combining this with the shading of C the only the part of the diagram not shaded would be that part of the 'overlap' of A and B which is not part of C. **
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RESPONSE --> We have a union with C, which includes all of C self critique assessment: 2
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15:09:30 2.3.114 Largest area of A shaded (sets A,B,C). Write a description using A, B, C, subset, union, intersection symbols, ', - for the shaded region.
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RESPONSE --> The region in color is in set A and is not in B and is not in C so we get A^B'^C' confidence assessment: 2
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15:10:23 ** Student Answer and Instructor Response: (B'^C')^A Instructor Response: Good. Another alternative would be A - (B U C ), and others are mentioned below. COMMON ERROR: A ^ (B' U C') INSTRUCTOR COMMENT: This is close but A ^ (B' U C') would contain all of B ^ C, including a part that's not shaded. A ^ (B U C)' would be one correct answer. **
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RESPONSE --> (B^C')^A is another response self critique assessment: 2
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course mth 151 {oS[ܼassignment #003
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14:13:31 Query 2.3.15 (Y ^ Z')U X, univ={a,..g}, X={a,c,e,g}, Y = {a,b,c}, Z = {b, ..., f} What is the set (Y ^ Z')U X?
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RESPONSE --> Z' IS {a,g} Y^Z' IS {a} because a is the only common element. So (Y^Z')UX = {a,c,e,g} the set of all elements that lie in at least one of the sets confidence assessment: 2
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14:14:17 **Z' = {a,g}, the set of all elements of the universal set not in Z. Y ^ Z' = {a}, since a is the only element common to both Y and Z'. So (Y ^ Z') U X = {a, c, e, g}, the set of all elements which lie in at least one of the sets (Y ^ Z') U X. **
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RESPONSE --> we wanted the set of all elements which lie in at least one of the sets. self critique assessment: 2
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14:17:47 Give the intersection of the two sets Y and Z'
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RESPONSE --> Y = {a,b,c} Z' = {a,g} set of elements common to both Y and Z' is {a} confidence assessment: 2
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14:18:23 **Z' = {a,g}, the set of all elements of the universal set not in Z. Y ^ Z' = {a}, since a is the only element common to both Y and Z'.**
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RESPONSE --> Z' is the set of all elements of the universal set no in Z self critique assessment: 2
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14:19:25 Query 2.3.30 describe in words (A ^ B' ) U (B ^ A')
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RESPONSE --> All elements that are in A but not in B, and all elements that are in B but not in A. confidence assessment: 2
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14:20:20 ** a description, not using a lot of set-theoretic terms, of (A ^ B' ) U (B ^ A') would be, all the elements that are in A and not in B, or that are not in A and are in B Or you might want to say something like 'elements which are in A but not B OR which are in B but not A'. STUDENT SOLUTION WITH INSTRUCTOR COMMENT:everything that is in set A and not in set B or everything that is in set B and is not in set A. INSTRUCTOR COMMENT: I'd avoid the use of 'everything' unless the word is necessary to the description. Otherwise it's likely to be misleading. **
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RESPONSE --> Ok I think I forgot my ' sign on my A', but I had the right idea. self critique assessment: 2
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14:25:45 2.3.51 always or not always true: n(A U B) = n(A)+n(B)
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RESPONSE --> it would be always true because n(A) is all elements in A and n(B) is all elements in B and when you add them together you get all elements that are in A and B, which is what the U of A and B is. confidence assessment: 2
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14:26:57 ** This conclusion is contradicted by many examples, including the one of the dark-haired and bright-eyed people in the q_a_. Basically n(A U B) isn't equal to n(A) + n(B) if there are some elements which are in both sets--i.e., in the intersection. } MORE DETAIL: The statement can be either true or false, depending on the sets A and B; it is not always true. The statement n(A U B) = n(A)+n(B) means that the number of elements in A U B is equal to the sum of the number of elements in A and the number of elements in B. The statement would be true for A = { c, f } and B = { a, g, h} because A U B would be { a, c, f, g, h} so n(A U B) = 5, and n(A) + n(B) = 2 + 3 = 5. The statement would not be true for A = { c, f, g } and B = { a, g, h} because A U B would be the same as before so n(AUB) = 5, while n(A) + n(B) = 3 + 3 = 6. The precise condition for which the statement is true is that A and B have nothing in common. In that case n(A U B) = n(A) + n(B). A more precise mathematical way to state this is to say that n(A U B) = n(A) + n(B) if and only if the intersection A ^ B of the two sets is empty. **
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RESPONSE --> Ok now that is just to tricky. But I do see what you mean self critique assessment: 2
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14:35:13 Query 2.3.60 X = {1,3,5}, Y = {1,2,3}. Find (X ^ Y)' and X' U Y'.
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RESPONSE --> (X^Y)' is all elements that is not in the ^ of X and Y, the intersection of X and Y is {1,3} so that leaves {2,5} being the intersection of (X^Y)' X' is everything not in X which is 5 and everything that is not in Y is 2 so X' U Y' = {2,5) confidence assessment: 2
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14:37:00 ** X ^ Y = {1,3} so (X ^ Y) ' = {1,3}' = {2, 4, 5}. (X ' U Y ' ) = {2, 4} U {4, 5} = {2, 4, 5} The two resulting sets are equal so a reasonable conjecture would be that (X ^ Y)' = X' U Y'. **
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RESPONSE --> Ok, I see what I did, I left the 4 out for the Universe. self critique assessment: 2
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14:44:06 2.3.72 A = {3,6,9,12}, B = {6,8}.
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RESPONSE --> AxB= {(3,6),(3,8),(6,6),(6,8),(9,6),(9,8),(12,6),(12,8)} BxA= {(6,3),(8,3),(6,6),(8,6),(6,9),(8,9),(6,12),(8,12)} confidence assessment: 2
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14:45:01 ** (A X B) = {(3,6),(3,8),(6,6),(6,8),(9,6),(9,8),(12,6), (12,8)} (B X A) = (6,3),(6,6),(6,9),(6,12),(8,3),(8,6),(8,9),(8,12)} How is n(A x B) related to n(A) and n(B)? n(S) stands for the number of elements in the set S, i.e., its cardinality. n(A x B) = n(A) * n(B) **
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RESPONSE --> n(S) stands for the number of elements in the set S self critique assessment: 2
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14:46:51 2.3.84 Shade A U B
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RESPONSE --> You would shade all elements in A and all elements in B which is section 2,3, and 4 in our book confidence assessment: 2
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14:47:31 ** everything in A and everything in B would be shaded. The rest of the universal set (the region outside A and B but still in the rectangle) wouldn't be. **
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RESPONSE --> the region outside A and B but still in the rectangle would not be shaded. self critique assessment: 2
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14:50:43 Query 2.3.100 Shade (A' ^ B) ^ C
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RESPONSE --> You would shade all elements that is not in A but is in B and all of C. confidence assessment: 2
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14:51:40 ** you would have to shade every region that lies outside of A and also inside B and also inside C. This would be the single region in the overlap of B and C but not including any part of A. Another way to put it: the region common to B and C, but not including any of A **
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RESPONSE --> every region that lies outside of A and also inside B and also inside C. self critique assessment: 2
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14:53:06 Describe the shading of the set (A ^ B)' U C.
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RESPONSE --> You would shade the section that is not in A or B which is C and C again. confidence assessment: 2
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14:53:36 ** All of C would be shaded because we have a union with C, which will include all of C. Every region outside A ^ B would also be shaded. A ^ B is the 'overlap' region where A and B meet, and only this 'overlap' would not be part of (A ^ B) '. The 'large' parts of A and B, as well as everything outside of A and B, would therefore be shaded. Combining this with the shading of C the only the part of the diagram not shaded would be that part of the 'overlap' of A and B which is not part of C. **
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RESPONSE --> We have a union with C, which includes all of C self critique assessment: 2
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15:09:30 2.3.114 Largest area of A shaded (sets A,B,C). Write a description using A, B, C, subset, union, intersection symbols, ', - for the shaded region.
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RESPONSE --> The region in color is in set A and is not in B and is not in C so we get A^B'^C' confidence assessment: 2
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15:10:23 ** Student Answer and Instructor Response: (B'^C')^A Instructor Response: Good. Another alternative would be A - (B U C ), and others are mentioned below. COMMON ERROR: A ^ (B' U C') INSTRUCTOR COMMENT: This is close but A ^ (B' U C') would contain all of B ^ C, including a part that's not shaded. A ^ (B U C)' would be one correct answer. **
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RESPONSE --> (B^C')^A is another response self critique assessment: 2
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course mth 151
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14:13:31 Query 2.3.15 (Y ^ Z')U X, univ={a,..g}, X={a,c,e,g}, Y = {a,b,c}, Z = {b, ..., f} What is the set (Y ^ Z')U X?
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RESPONSE --> Z' IS {a,g} Y^Z' IS {a} because a is the only common element. So (Y^Z')UX = {a,c,e,g} the set of all elements that lie in at least one of the sets confidence assessment: 2
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14:14:17 **Z' = {a,g}, the set of all elements of the universal set not in Z. Y ^ Z' = {a}, since a is the only element common to both Y and Z'. So (Y ^ Z') U X = {a, c, e, g}, the set of all elements which lie in at least one of the sets (Y ^ Z') U X. **
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RESPONSE --> we wanted the set of all elements which lie in at least one of the sets. self critique assessment: 2
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14:17:47 Give the intersection of the two sets Y and Z'
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RESPONSE --> Y = {a,b,c} Z' = {a,g} set of elements common to both Y and Z' is {a} confidence assessment: 2
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14:18:23 **Z' = {a,g}, the set of all elements of the universal set not in Z. Y ^ Z' = {a}, since a is the only element common to both Y and Z'.**
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RESPONSE --> Z' is the set of all elements of the universal set no in Z self critique assessment: 2
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14:19:25 Query 2.3.30 describe in words (A ^ B' ) U (B ^ A')
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RESPONSE --> All elements that are in A but not in B, and all elements that are in B but not in A. confidence assessment: 2
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14:20:20 ** a description, not using a lot of set-theoretic terms, of (A ^ B' ) U (B ^ A') would be, all the elements that are in A and not in B, or that are not in A and are in B Or you might want to say something like 'elements which are in A but not B OR which are in B but not A'. STUDENT SOLUTION WITH INSTRUCTOR COMMENT:everything that is in set A and not in set B or everything that is in set B and is not in set A. INSTRUCTOR COMMENT: I'd avoid the use of 'everything' unless the word is necessary to the description. Otherwise it's likely to be misleading. **
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RESPONSE --> Ok I think I forgot my ' sign on my A', but I had the right idea. self critique assessment: 2
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14:25:45 2.3.51 always or not always true: n(A U B) = n(A)+n(B)
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RESPONSE --> it would be always true because n(A) is all elements in A and n(B) is all elements in B and when you add them together you get all elements that are in A and B, which is what the U of A and B is. confidence assessment: 2
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14:26:57 ** This conclusion is contradicted by many examples, including the one of the dark-haired and bright-eyed people in the q_a_. Basically n(A U B) isn't equal to n(A) + n(B) if there are some elements which are in both sets--i.e., in the intersection. } MORE DETAIL: The statement can be either true or false, depending on the sets A and B; it is not always true. The statement n(A U B) = n(A)+n(B) means that the number of elements in A U B is equal to the sum of the number of elements in A and the number of elements in B. The statement would be true for A = { c, f } and B = { a, g, h} because A U B would be { a, c, f, g, h} so n(A U B) = 5, and n(A) + n(B) = 2 + 3 = 5. The statement would not be true for A = { c, f, g } and B = { a, g, h} because A U B would be the same as before so n(AUB) = 5, while n(A) + n(B) = 3 + 3 = 6. The precise condition for which the statement is true is that A and B have nothing in common. In that case n(A U B) = n(A) + n(B). A more precise mathematical way to state this is to say that n(A U B) = n(A) + n(B) if and only if the intersection A ^ B of the two sets is empty. **
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RESPONSE --> Ok now that is just to tricky. But I do see what you mean self critique assessment: 2
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14:35:13 Query 2.3.60 X = {1,3,5}, Y = {1,2,3}. Find (X ^ Y)' and X' U Y'.
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RESPONSE --> (X^Y)' is all elements that is not in the ^ of X and Y, the intersection of X and Y is {1,3} so that leaves {2,5} being the intersection of (X^Y)' X' is everything not in X which is 5 and everything that is not in Y is 2 so X' U Y' = {2,5) confidence assessment: 2
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14:37:00 ** X ^ Y = {1,3} so (X ^ Y) ' = {1,3}' = {2, 4, 5}. (X ' U Y ' ) = {2, 4} U {4, 5} = {2, 4, 5} The two resulting sets are equal so a reasonable conjecture would be that (X ^ Y)' = X' U Y'. **
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RESPONSE --> Ok, I see what I did, I left the 4 out for the Universe. self critique assessment: 2
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14:44:06 2.3.72 A = {3,6,9,12}, B = {6,8}.
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RESPONSE --> AxB= {(3,6),(3,8),(6,6),(6,8),(9,6),(9,8),(12,6),(12,8)} BxA= {(6,3),(8,3),(6,6),(8,6),(6,9),(8,9),(6,12),(8,12)} confidence assessment: 2
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14:45:01 ** (A X B) = {(3,6),(3,8),(6,6),(6,8),(9,6),(9,8),(12,6), (12,8)} (B X A) = (6,3),(6,6),(6,9),(6,12),(8,3),(8,6),(8,9),(8,12)} How is n(A x B) related to n(A) and n(B)? n(S) stands for the number of elements in the set S, i.e., its cardinality. n(A x B) = n(A) * n(B) **
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RESPONSE --> n(S) stands for the number of elements in the set S self critique assessment: 2
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14:46:51 2.3.84 Shade A U B
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RESPONSE --> You would shade all elements in A and all elements in B which is section 2,3, and 4 in our book confidence assessment: 2
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14:47:31 ** everything in A and everything in B would be shaded. The rest of the universal set (the region outside A and B but still in the rectangle) wouldn't be. **
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RESPONSE --> the region outside A and B but still in the rectangle would not be shaded. self critique assessment: 2
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14:50:43 Query 2.3.100 Shade (A' ^ B) ^ C
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RESPONSE --> You would shade all elements that is not in A but is in B and all of C. confidence assessment: 2
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14:51:40 ** you would have to shade every region that lies outside of A and also inside B and also inside C. This would be the single region in the overlap of B and C but not including any part of A. Another way to put it: the region common to B and C, but not including any of A **
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RESPONSE --> every region that lies outside of A and also inside B and also inside C. self critique assessment: 2
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14:53:06 Describe the shading of the set (A ^ B)' U C.
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RESPONSE --> You would shade the section that is not in A or B which is C and C again. confidence assessment: 2
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14:53:36 ** All of C would be shaded because we have a union with C, which will include all of C. Every region outside A ^ B would also be shaded. A ^ B is the 'overlap' region where A and B meet, and only this 'overlap' would not be part of (A ^ B) '. The 'large' parts of A and B, as well as everything outside of A and B, would therefore be shaded. Combining this with the shading of C the only the part of the diagram not shaded would be that part of the 'overlap' of A and B which is not part of C. **
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RESPONSE --> We have a union with C, which includes all of C self critique assessment: 2
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15:09:30 2.3.114 Largest area of A shaded (sets A,B,C). Write a description using A, B, C, subset, union, intersection symbols, ', - for the shaded region.
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RESPONSE --> The region in color is in set A and is not in B and is not in C so we get A^B'^C' confidence assessment: 2
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15:10:23 ** Student Answer and Instructor Response: (B'^C')^A Instructor Response: Good. Another alternative would be A - (B U C ), and others are mentioned below. COMMON ERROR: A ^ (B' U C') INSTRUCTOR COMMENT: This is close but A ^ (B' U C') would contain all of B ^ C, including a part that's not shaded. A ^ (B U C)' would be one correct answer. **
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RESPONSE --> (B^C')^A is another response self critique assessment: 2
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