course Mth 151 ˆçêÅw½¸àº°õ¶ïy¿à’ÕÑassignment #006
......!!!!!!!!...................................
21:56:32 `q001. Note that there are 6 questions in this assignment. Find the likely next element of the sequence 1, 2, 4, 7, 11, ... .
......!!!!!!!!...................................
RESPONSE --> the next element would be 16 because 1+1 =2 2+2=4 4+3 = 7 7+4= 11 11+5= 16 confidence assessment: 2
.................................................
......!!!!!!!!...................................
21:57:16 The difference between 1 and 2 is 1; between 2 and 4 is 2; between 4 and 7 is 3; between 7 and 11 is 4. So we expect that the next difference will be 5, which will make the next element 11 + 5 = 16.
......!!!!!!!!...................................
RESPONSE --> by 1,2,3,4,5 self critique assessment: 2
.................................................
......!!!!!!!!...................................
22:07:08 `q002. Find the likely next two elements of the sequence 1, 2, 4, 8, 15, 26, ... .
......!!!!!!!!...................................
RESPONSE --> the answer is 1,2,4,8,15,26,32,44 I got the answer by the use of the method of successive differences. confidence assessment: 2
.................................................
......!!!!!!!!...................................
22:09:14 The difference between 1 and 2 is 1; the difference between 2 and 4 is 2, the difference between 4 and 8 is 4; the difference between 8 and 15 is 7; the difference between 15 and 26 is 11. The differences form the sequence 1, 2, 4, 7, 11, ... . As seen in the preceding problem the differences of this sequence are 1, 2, 3, 4, ... . We would expect the next two differences of this last sequence to be 5 and 6, which would extend the sequence 1, 2, 4, 7, 11, ... to 1, 2, 4, 7, 11, 16, 22, ... . If this is the continuation of the sequence of differences for the original sequence 1, 2, 4, 8, 15, 26, ... then the next two differences of this sequence would be 16 , giving us 26 + 16 = 42 as the next element, and 22, giving us 42 + 26 = 68 as the next element. So the original sequence would continue as 1, 2, 4, 8, 15, 26, 42, 68, ... .
......!!!!!!!!...................................
RESPONSE --> oK i GOT THAT ONE WRONG. extend the sequence 1,2,4,7,11,16,22 self critique assessment: 2
.................................................
......!!!!!!!!...................................
22:10:14 `q003. What would be the likely next element in the sequence 1, 2, 4, 8, ... . It is understood that while this sequence starts off the same as that in the preceding exercise, it is not the same. The next element is not 15, and the pattern of the sequence is different than the pattern of the preceding.
......!!!!!!!!...................................
RESPONSE --> you are doubling each number, so the next element would be 16 confidence assessment: 2
.................................................
......!!!!!!!!...................................
22:10:40 One obvious pattern for this sequence is that each number is doubled to get the next. If this pattern continues then the sequence would continue by doubling 8 to get 16. The sequence would therefore be 1, 2, 4, 8, 16, ... .
......!!!!!!!!...................................
RESPONSE --> each number is doubled to get the next self critique assessment: 2
.................................................
......!!!!!!!!...................................
22:17:10 `q004. There are two important types of patterns for sequences, one being the pattern defined by the differences between the numbers of the sequence, the other being the pattern defined by the ratios of the numbers of the sequence. In the preceding sequence 1, 2, 4, 8, 16, ..., the ratios were 2/1 = 2; 4/2 = 2; 8/4 = 2; 16/8 = 2. The sequence of ratios for 1, 2, 4, 8, 16, ..., is thus 2, 2, 2, 2, a constant sequence. Find the sequence of ratios for the sequence 32, 48, 72, 108, ... , and use your result to estimate the next number and sequence.
......!!!!!!!!...................................
RESPONSE --> 32/48 = 1.5, 72/108 = 1.5, to find the next element we would multiply 108*1.5 and the answer is 162. confidence assessment: 2
.................................................
......!!!!!!!!...................................
22:17:47 The ratios are 48/32 = 1.5; 72 / 48 = 1.5; 108/72 = 1.5, so the sequence of ratios is 1.5, 1.5, 1.5, 1.5, ... . The next number the sequence should probably therefore be 108 * 1.5 = 162.
......!!!!!!!!...................................
RESPONSE --> 1.5 sequence of ratios self critique assessment: 2
.................................................
......!!!!!!!!...................................
22:21:00 `q005. Find the sequence of ratios for the sequence 1, 2, 3, 5, 8, 13, 21... , and estimate the next element of the sequence.
......!!!!!!!!...................................
RESPONSE --> if you do 2/1 = 2 and if you do 5/3 you get an infinate 1.6, and if you 13/8 you get 1.625 so I really don't know how to get this one confidence assessment: 2
.................................................
......!!!!!!!!...................................
22:21:53 The ratios are 2/1 = 2; 3/2 = 1.5; 5/3 = 1.66...; 8/5 = 1.60; 13/8 = 1.625; 21/13 = 1.615. The sequence of ratios is 2, 1.5, 1.66..., 1.625, 1.615, ... . We see that each number in the sequence lies between the two numbers that precede it -- 1.66... lies between 2 and 1.5; 1.60 lies between 1.5 and 1.66...; 1.625 lies between 1.66... and 1.60; 1.615 lies between 1.60 and 1.625. We also see that the numbers in the sequence alternate between being greater than the preceding number and less than the preceding number, so that the intervals between the numbers get smaller and smaller. So we expect that the next number in the sequence of ratios will be between 1.615 and 1.625, and if we pay careful attention to the pattern we expect the next number to be closer to 1.615 than to 1.625. We might therefore estimate that the next ratio would be about 1.618. We would therefore get 1.618 * 21 = 33.98 for the next number in the original sequence. However, since the numbers in the sequence are all whole numbers, we round our estimate up to 34. Our conjecture is that the sequence continues with 1, 2, 3, 5, 8, 13, 21, 34, ... .
......!!!!!!!!...................................
RESPONSE --> that's just a little too difficult starting out. self critique assessment: 2
.................................................
......!!!!!!!!...................................
22:27:33 `q006. Without using ratios, can you find a pattern to the sequence 1, 1, 2, 3, 5, 8, 13, 21, 34, ..., and continue the sequence for three more numbers?
......!!!!!!!!...................................
RESPONSE --> ok 1+1=2, 2+3=5, 3+5=8, etc. the next 3 elements would be 55,89,144 confidence assessment: 2
.................................................
......!!!!!!!!...................................
22:28:07 The pattern is that each element from the third on is the sum of the two elements that precede it. That is, 1+1=2, 2+1=3; 3+2=5; 5+3=8; 8+5=13; 13+8=21; 21+13=34; . The next three elements would therefore e 34+21=55; 55+34=89; 89+55=144. . The sequence is seen to be 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, ... .
......!!!!!!!!...................................
RESPONSE --> add 1st number to the next number and get the next number self critique assessment: 2
.................................................