course Mth 151 w÷ã‹Îxäxão·éÑ¥M{׸Ë_ý–ÃÒïõÝõassignment #018
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12:14:28 `q001. There are 5 questions in this set. From lectures and textbook you will learn about some of the counting systems used by past cultures. Various systems enabled people to count objects and to do basic arithmetic, but the base-10 place value system almost universally used today has significant advantages over all these systems. The key to the base-10 place value system is that each digit in a number tells us how many times a corresponding power of 10 is to be counted. For example the number 347 tells us that we have seven 1's, 4 ten's and 3 one-hundred's, so 347 means 3 * 100 + 4 * 10 + 7 * 1. Since 10^2 = 100, 10^1 = 10 and 10^0 = 1, this is also written as 3 * 10^2 + 4 * 10^1 + 7 * 10^0. How would we write 836 in terms of powers of 10?
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RESPONSE --> (8*10^2) + (3*10^1) + (6*10^0) = 836 confidence assessment: 2
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12:15:14 836 means 8 * 100 + 3 * 10 + 6 * 1, or 8 * 10^2 + 3 * 10^1 + 6 * 10^0.
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RESPONSE --> 836 mean 8*100+3*10+6*1 self critique assessment: 2
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12:17:23 `q002. How would we write 34,907 in terms of powers of 10?
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RESPONSE --> (3*10,000)+(4*1,000)+(9*100)+(0*10)+(7*1) means 34,907 confidence assessment: 2
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12:17:42 34,907 means 3 * 10,000 + 4 * 1000 + 9 * 100 + 0 * 10 + 7 * 1, or 3 * 10^4 + 4 * 10^3 + 9 * 10^2 + 0 * 10 + 7 * 1.
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RESPONSE --> this is the answer that I got self critique assessment: 2
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12:20:09 `q003. How would we write .00326 in terms of powers of 10?
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RESPONSE --> I have no idea confidence assessment: 0
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12:23:18 First we note that .1 = 1/10 = 1/10^1 = 10^-1, .01 = 1/100 = 1/10^2 = 10^-2, .001 = 1/1000 = 1/10^3 = 10^-3, etc.. Thus .00326 means 0 * .1 + 0 * .01 + 3 * .001 + 2 * .0001 + 6 * .00001 = 0 * 10^-1 + 0 * 10^-2 + 3 * 10^-3 + 2 * 10^-4 + 6 * 10^-5 .
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RESPONSE --> ok so .00326 is (0*.1)+(0*.01)+(3*.001)+(2*.0001)+(6*.00001) self critique assessment: 2
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12:25:31 `q004. How would we add 3 * 10^2 + 5 * 10^1 + 7 * 10^0 to 5 * 10^2 + 4 * 10^1 + 2 * 10^0?
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RESPONSE --> 350+ 542= 892 means 8*10^2 + 9*10^1 + 2*10^0 confidence assessment: 2
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12:26:00 We would write the sum as (3 * 10^2 + 5 * 10^1 + 7 * 10^0) + (5 * 10^2 + 4 * 10^1 + 2 * 10^0) , which we would then rearrange as (3 * 10^2 + 5 * 10^2) + ( 5 * 10^1 + 4 * 10^1) + ( 7 * 10^0 + 2 * 10^0), which gives us 8 * 10^2 + 9 * 10^1 + 9 * 10^0. This result would then be written as 899.
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RESPONSE --> ok I done something wrong on that one self critique assessment: 2
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12:28:04 `q005. How would we add 4 * 10^2 + 7 * 10^1 + 8 * 10^0 to 5 * 10^2 + 6 * 10^1 + 4 * 10^0?
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RESPONSE --> that would be 1,042 1*10^3 + 0*10^2 + 4*10^2 + 2 *10^0 confidence assessment: 2
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12:28:59 We would write the sum as (4 * 10^2 + 7 * 10^1 + 8 * 10^0) + (5 * 10^2 + 6 * 10^1 + 4 * 10^0) , which we would then rearrange as (4 * 10^2 + 5 * 10^2) + ( 7 * 10^1 + 6 * 10^1) + ( 8 * 10^0 + 4 * 10^0), which gives us 9 * 10^2 + 13 * 10^1 + 12 * 10^0. Since 12 * 10^0 = (2 + 10 ) * 10^0 = 2 * 10^0 + 10^1, we have 9 * 10^2 + 13 * 10^1 + 1 * 10^1 + 2 * 10^0 = 9 * 10^2 + 14 * 10^1 + 2 * 10^0. Since 14 * 10^1 = 10 * 10^1 + 4 * 10^1 = 10^2 + 4 * 10^1, we have 9 * 10^2 + 1 * 10^2 + 4 * 10^1 + 2 * 10^0 = 10^10^2 + 4 * 10^1 + 2 * 10^0. Since 10*10^2 = 10^3, we rewrite this as 1 * 10^3 + 0 * 10^2 + 4 * 10^1 + 2 * 10^0. This number would be expressed as 1042.
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RESPONSE --> Ok I don't have this adding yet, need to practice somemore on that. self critique assessment: 2
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