phy 121
This looks good for the most part. See my note.
In the collision experiment from Friday my group setup a 2 ramps one short closest to the edge of the table and one longer ramp connecting to the shorter ramp. The longer ramp was inclined about 10 cm. We dropped the steel ball at the edge of the table onto carbon paper to determine where to start measurements from once we had our data. Then we rolled the steel ball down the ramp, and let it hit carbon paper on the floor to determine how far it would go off the table. We then set up our glass ball at the edge of the table where the steel ball would meet it centered when they collided. We used a straw to set the marble on to get it centered. Once we had the glass marble in place, we rolled the steel ball down the ramp so it would collide with the glass ball. After the steel ball collided with the glass ball we measured how far out the balls went by placing carbon paper on the spots they hit in the trials runs. We did 3-4 trials for determining where to place the carbon paper for the ball without the collision and for both balls in the collision. After we got out measurements we raised the every part of the ramp 1mm and repeated the experiment to get another set of data.
I measured my marks again before I started working through the analysis and It came up slightly different, but more accurate than the last set.Steel ball off ramp-34.5Steel ball hit-23.4glass ball hit-501mm higherSteel ball off ramp-33.5Steel ball hit-16.4glass ball hit-48.7
When I was working the problem for KE I got:
ball 1 before-.5(60)(80)^2=192,000ball 1 after-.5(60)(54)^2=87,480
ball 2 before-0
ball 2 after-.5(12)(50)^2=15000
I'm just a little confused with ball 2 after. If you could point me in the right direction I should be able to figure out he rest.
I believe you got your velocities by dividing the horizontal ranges by the .43 second time interval.
However in calculating the velocity of ball 2 after, you didn't divide the 50 cm by .43 seconds and just used 50 as the velocity. Divide it out to get velocity in cm / sec and then see what the energy is.