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course Phy 232
7/25:30
If you are unable to attempt a solution, give a phrase-by-phrase interpretation of the problem along with a statement of what you do or do not understand about it. This response should be given, based on the work you did in completing the assignment, before you look at the given solution.
002. `query 2
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Question: from Introductory Problem Set 5 # 11: Finding the conductivity given rate of energy flow, area, temperatures, thickness of wall.
Describe how we find the conductivity given the rate of energy flow, area, temperatures, and thickness of the wall.
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Your Solution:
Since the rate of thermal energy conduction is equal to conductivity times
the area of the wall times the temperature gradient, you have to solve for
conductivty. When you do this, you have rate of conduction divided by the
area of the wall and the temperature gradient. Then you plug in the numbers
that you have been given:
conductivity=64.4 w / ((2m^2)*(353.125 C/m))
conductivity=9.12 x 10^-2 w/Cm"
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