Assignment 14Query14

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course Mth 151

014. `query 14

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Question: `q3.3.5 rewrite using if then ' all marines love boot camp '.

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Your solution:

‘If they are a marine, they love boot camp’

confidence rating #$&*: 2

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Given Solution:

`a** The statement is equivalent to 'If it's a Marine, it loves boot camp' or equivalent.

The statement is not equivalent to 'if it is boot camp, then all Marines love it', which is the converse of the original statement. **

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Self-critique (if necessary): OK

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Self-critique Rating: 3

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Question: `q3.3.18 ~p false q false p -> q true

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Your solution:

~p being false makes it true

q is just false

T -> F, which is a false statement

confidence rating #$&*: 2

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Given Solution:

`a** Since ~p is false then p is true.

Since q is false it follows that p -> q is of the form T -> F, which is false.

The conditional is false when, and only when, the antecedent is true and the consequent false. **

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Self-critique (if necessary): OK

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Self-critique Rating: 2

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Question: `qQuery 3.3.36 write in symbols 'If we don't bike, then it does not rain.'

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Your solution:

~p -> ~q

confidence rating #$&*: 2

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Given Solution:

`a** If p stands for 'don't bike' and r for 'it rains' then the statement would be p -> ~r. **

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Self-critique (if necessary): I don’t understand why “we don’t bike” is just p and not ~p. Wouldn’t the negation of “we don’t” be “we do”???

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Self-critique Rating: 1

@&

The user defines the meanings of the symbols. Once defined their meanings are as stated.

But it would be clearer to define it the way you didn.

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Question: `qQuery 3.3.48 q true, p and r false, evaluate (~r U p) -> p

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Your solution:

(r U p)

(T U F)

T -> p

T -> F, so the entire statement is false

confidence rating #$&*: 2

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Given Solution:

`a** The antecedent (~r U p ) would be true, since ~r true and p false.

The consequent p would be false.

Since the antecedent is true and the consequent false, the conditional is false. **

MORE DETAILED SOLUTION

r is said to be false, so ~r is true

p is said to be false

Therefore the disjunction (~r U p) would be a disjunction of a true and a false statement.

A disjunction is true if at least one of the statements is true, so (~r U p) is true.

The conditional (~r U p) -> p therefore consists of an antecedent which is true, and a consequent which is false.

By the rules for a conditional, the statement is therefore false.

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Self-critique (if necessary): OK

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Self-critique Rating: 2

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Question: `qQuery 3.3.60 truth table for (p ^ q) -> (p U q)

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Your solution:

p q (p ^ q) (p U q) (p ^ q) -> (p U q)

T T T T T

T F F T T

F T F T T

F F F F T

confidence rating #$&*: 3

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Given Solution:

`a** The headings would be p, q ,(p^q), (pUq), (p^q)->(pUq)

Row 1 would read T T T T T

Row 2 would read T F F T T

Row 3 would read F T F T T

Row 4 would read F F F F T

The common sense of this is that whenever both p and q are true, then the statement 'p or q' must be true. That's what means to say (p ^ q) -> (p U q).

The fact that this statement is true is indicated by the last column of the truth table, which has True in every possible case. **

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Self-critique (if necessary): OK. True tables have been giving me a lot of problems so I’m very excited to know I understood one, finally.

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Self-critique Rating: 3

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Very good.

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Question: `qQuery 3.3.74 (formerly 3.3.72). This wasn't assigned but it is similar to assigned questions and should be answered: What is the negation of the statement 'if loving you is wrong then I don't want to be right' ?

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Your solution:

‘If you loving you is wrong then I want to be right’

confidence rating #$&*: 1

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Given Solution:

`a** The negation has to have the exact opposite truth values of the original statement.

It is difficult and confusing to try to negate a conditional. It is much easier to translate the conditional to a disjunction then negate the disjunction. It is easy to negate the disjunction using deMorgan's Laws.

Since p -> q is identical to ~p U q, the negation of p -> q is ~ ( ~p U q), which by de Morgan's Law is ~ ~p ^ ~q, or just p ^ ~q.

So the negation would ge 'loving you is wrong AND I want to be right.

COMMON ERROR AND NOTE: If loving you is wrong, then I want to be right.

INSTRUCTOR COMMENT:

The negation of a conditional can't be a conditional (a conditional is false in only one case so its negation would have to be false in three cases). **

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Self-critique (if necessary): I understand how negation works but I didn’t consider the “and”

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Self-critique Rating: 2

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#*&!

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