open query 2

#$&*

course Mth 151

1/23

If your solution to stated problem does not match the given solution, you should self-critique per instructions at

http://vhcc2.vhcc.edu/dsmith/geninfo/labrynth_created_fall_05/levl1_22/levl2_81/file3_259.htm

Your solution, attempt at solution. If you are unable to attempt a solution, give a phrase-by-phrase interpretation of the problem along with a statement of what you do or do not understand about it. This response should be given, based on the work you did in completing the assignment, before you look at the given solution.

002. `Query 2

*********************************************

Question: `q2.2.24 U={a,b,...,g}, A={a,e}, B={a,b,e,f,g}, C={b,f,g}, D={d,e} Is C ps U?

Is the statement true or false and why?

YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY

Your solution:

Yes it is true because everything that is in the set C is in the set U and not everything in U is in C and for this to be tru they cannot be the same.

confidence rating #$&*: 3

^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

.............................................

Given Solution:

`a** It's true because all elements of C are in the universal set, and because there are elements of U that aren't in C. You have to have both conditions, since a proper subset cannot be identical to other set. **

&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&

Self-critique (if necessary):

------------------------------------------------

Self-critique Rating:3

*********************************************

Question: `qQuery 2.2.30 phi s D

YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY

Your solution:

?

confidence rating #$&*: 0

^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

.............................................

Given Solution:

`a** Note that You should be responding to problem 2.2.30 from the homework you worked out on paper. The shorthand notation is for my reference and won't always make sense to you. For clarification, though, the symbol for the empty set is the Greek letter phi.

One set is a subset of another if every element of that set is in the other. To show that a set isn't a subset of another you have to show something in that set that isn't in the other.

There's nothing in the empty set so you can never do this--you can never show that it has something the other set doesn't. So you can never say that the empty set isn't a subset of another set.

Thus the empty set is a subset of any given set, and in particular it's a subset of D.

ALTERNATIVE ANSWER: As the text tells you, the empty set is a subset of every set.

ANOTHER ALTERNATIVE

Every element of the empty set is in D because there is no element in the empty set available to lie outside of D.

ONE MORE ALTERNATIVE: The empty set is a subset of every set. Any element in an empty set is in any set, since there's nothing in the empty set to contradict that statement. **

&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&

Self-critique (if necessary):

I was a little confused on this one…so I looked at the given solution and referred to my notes and homework. Does this mean that phi s D will equal anything..or in other words equal any set???????????????????????????????

------------------------------------------------

Self-critique Rating:3

@& The given solution never mentions phi. You should answer in terms of the problem as stated in your book, with no need for the abbreviated statement in this document.*@

*********************************************

Question: `q2.2.33 D not s B

Is the statement true or false and why?

YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY

Your solution:

?

confidence rating #$&*:0

^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

.............................................

Given Solution:

`a** D is a subset of B if every element of D is an element of B-i.e., if D doesn't contain anything that B doesn't also contain.

The statement says that D is not a subset of B. This will be so if D contains at least one element that B doesn't. **

&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&

Self-critique (if necessary):

Im still confused on the subsets…The wording has be confused!

------------------------------------------------

Self-critique Rating:3

@& Again you should reference the solution you wrote down when you did the problems in your text, where the statement was made in standard notation.*@

*********************************************

Question: `q2.2.36 there are exactly 31 subsets of B

YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY

Your solution:

This is false because B contains 5 and 2^5=2*2*2*2*2=32

confidence rating #$&*: 3

^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

.............................................

Given Solution:

`a** If a set has n elements then is has 2^n subsets, all but one of which are proper subsets. B has 5 elements so it has 2^5 = 32 subsets. So the statement is false.

There are exactly 31 proper subsets of B, but there are 32 subsets of B. **

&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&

Self-critique (if necessary):

------------------------------------------------

Self-critique Rating:3

*********************************************

Question: `qQuery 2.2.40 there are exactly 127 proper subsets of U

Is the statement true or false and why?

YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY

Your solution:

There are 7 in the set U and 2^7=128 not 127

confidence rating #$&*: 2

^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

.............................................

Given Solution:

`a** The set is not a proper subset of itself, and the set itself is contained in the 2^n = 2^7 = 128 subsets of this 7-element set. This leaves 128-1 = 127 proper subsets. **

&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&

Self-critique (if necessary):

------------------------------------------------

Self-critique Rating:3

*********************************************

Question: `qQuery 2.2.48 U={1,2,...,10}, complement of {2,5,7,9,10}

What is the complement of the given set?

YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY

Your solution:

The complement of the given set is {1, 3, 4, 6, 8} because these are the numbers that are not the complement of {2,5,7,9,10}

confidence rating #$&*: 3

^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

.............................................

Given Solution:

`a** the complement is {1,3,4,6,8}, the set of all elements in U that aren't in the given set. **

&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&

Self-critique (if necessary):

I worded it differently

------------------------------------------------

Self-critique Rating:3

*********************************************

Question: `qquery 2.2.63 in how many ways can 3 of the five people A, B, C, D, E gather in a suite?

YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY

Your solution:

You need to list the different ways only 3 people can gather in a suite.

{a,b,c){a,b,d}{a,b,e}{a,c,d}{a,c,e}{a,d,e}{b,c,d}{b,c,e}{b,d,e}{c, d, e}

10 ways

confidence rating #$&*: 3

*********************************************

Question: `qquery 2.2.63 in how many ways can 3 of the five people A, B, C, D, E gather in a suite?

YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY

Your solution:

You need to list the different ways only 3 people can gather in a suite.

{a,b,c){a,b,d}{a,b,e}{a,c,d}{a,c,e}{a,d,e}{b,c,d}{b,c,e}{b,d,e}{c, d, e}

10 ways

confidence rating #$&*: 3

#(*!

&#Good responses. See my notes and let me know if you have questions. &#