#$&*
course Phy 231
3/12 2
A projectile leaves the edge of a table and, while traveling horizontally at a constant 28 cm/s, falls freely a distance of 80 cm to the floor. If its vertical acceleration is 980 cm/s2, how long does it take to fall and how far does it travel in the horizontal direction during the fall?I drew a picture of a ledge with a car on top and vox = 28 cm/s.
I made 'dy = 80 cm from the top of the ledge to the ground.
I then reasoned out the voy = 0cm/s, and had vfy = ?
vfy = 'sqrt (2 * a * 'ds) = 'sqrt (2 * 980 cm/s^2 * 80 cm) = 395.979 cm / s, unrounded.
vAvey = (395.979 cm / s) / 2 = 197.989 cm/s
'ds = vAve * 'dt,
'dt = 'ds / vAve = 80 cm / 197.989 cm/s = 0.40406 s = 0.40 s = 'dt (2 sigs)
vox = 28 cm/s, vfx = 28cm/s, 'dt = 0.40 s
vAvex = 56 cm/s / 2 = 28 cm/s
'dsx = Vave * 'dt = 28 cm/s * 0.40 s = 11 cm
'dt = 0.40 s, 'dsx = 11 cm
&#Very good responses. Let me know if you have questions. &#