cq_1_111

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Phy 231

Your 'cq_1_11.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

** CQ_1_11.1_labelMessages **

Answer the following based on Newton's Second Law:

How much net force is required to accelerate a 12 kg mass at 3 m/s^2?

answer/question/discussion: ->->->->->->->->->->->-> :

Fnet = mass*a = 12 kg * 3m/s^2 = 36 N

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What would be the acceleration of a 4 kg mass subject to a net force of 20 Newtons?

answer/question/discussion: ->->->->->->->->->->->-> :

fnet = m*a

20 N = 4 kg * a

a = 5 m/s^2

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If you exert a force of 20 Newtons on a 10-kg object and it accelerates in the direction of your force at 1.5 m/s^2, then how do you know there are other forces acting on the object besides your own?

answer/question/discussion: ->->->->->->->->->->->-> :

Fnet push alone = m * a

20 N = 10kg * a

a = 2 m/s^2

2 m/s^2 > 1.5m/s^2

So there is a force pushing back on the applied force, or has an opposite nmagnitude

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What is the total of all those forces and in what direction does this total act?

answer/question/discussion: ->->->->->->->->->->->-> :

fnet = fpush + fagainst

fnet = m*a + m2*a = 10 kg*2 m/s^2 - 10 kg * 0.5 m/s^2 = 15N

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&#Good responses. Let me know if you have questions. &#