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Phy 231
Your 'cq_1_12.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_12.1_labelMessages **
Masses of 5 kg and 6 kg are suspended from opposite sides of a light frictionless pulley and are released.
What will be the net force on the 2-mass system and what will be the magnitude and direction of its acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
Net force = fcons + fcons
Net Force = 6 kg * 9.8m/s^2 + (-5kg*9.8m/s^2) = 9.8 Newtons.
the net force will be 9.8 Newtons in the direction of the larger (6 kg weight)
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If you give the system a push so that at the instant of release the 5 kg object is descending at 1.8 meters / second, what will be the speed and direction of motion of the 5 kg mass 1 second later?
answer/question/discussion: ->->->->->->->->->->->-> :
fnet = mass * Accel
Accel = fnet / mass
Accel = 9.8 N / (5 + 6) kg = 0.8909 m/s^2
accel is 0.8909 m/s^2 in direction opposite motion
vf = vo + a*'dt
vf = 1.8 m/s + (-0.8909 m/s^2) * 1 sec = 0.91 m/s
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During the first second, are the velocity and acceleration of the system in the same direction or in opposite directions, and does the system slow down or speed up?
answer/question/discussion: ->->->->->->->->->->->-> :
During the first second the velocity and acceleration are in opposite directions, so the system is slowing down.
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10 mins
&#Very good responses. Let me know if you have questions. &#