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Phy 231
Your 'cq_1_19.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_19.2_labelMessages **
Sketch a vector representing a 10 Newton force which acts vertically downward.
Position an x-y coordinate plane so that the initial point of your vector is at the origin, and the angle of the vector as measured counterclockwise from the positive x axis is 250 degrees. This will require that you 'rotate' the x-y coordinate plane from its traditional horizontal-vertical orientation.
answer/question/discussion: ->->->->->->->->->->->-> :
Regular angle of force = 270 degrees
shift of axis so vector is 250 degrees from x axis = 270 degrees - 250 degrees = 20 degree rotation.
Axis is rotated 20 degrees CCW to have vector 225 degrees from x axis.
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That would be 250 degrees, but yes.
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What are the x and y components of the equilibrant of the force?
answer/question/discussion: ->->->->->->->->->->->-> :
Fx regular = 10 N cos 250 = -3.42 N
FyRegual = 10 N sin 250 = -9.40 N
FxEquilibrant = +3.42 N
Fy Exuilibrant = 9.40 N
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&#Good responses. See my notes and let me know if you have questions. &#