You need to include a concise description of your setup for each part of the experiment, relating your data to what you actually did. Please insert that so I can tell exactly the data mean. I can almost tell, but I need a little more informaion.
Here is my raw data for the first
part:
Rubber band Length(cm) F applied on rod(cm) Fnet(Newtons)
Torques
A 10.5 7.5 2.8 29.4
B
9.5 .4 1.7 16.15
c 11.0
12 3.25 35.75
The ""F applied on rod"" is where the
paper clip was at on the rod from the left side. As far
as I can see the percent of
the net force of the magnitudes would be 25% of the sum of all
four. Is that too
simple or am I on?
My data on the second part is :
Rubber band Length(cm) F
applied on rod(cm) Fnet(Newtons) Torques
A 11 .4
3.25 35.75
B 10 2.1
2.3 23
c 11 11.2
3.25 35.75
D 10 14.7 2.3
23
I believe that the way the example shows the 4 net forces being totalled up is wrong.
You
said that the forces going in a clockwise direction were negative but you don't
reflect that
for the for ""A"" and ""B"". They need to be reversed to the other side
of the sign. That
would change the answer to 1.2.
The sum of the vertical forces in
mine is - 1.9. I found that my rubber bands were not in
the same scale as your
picture. The A and C were my longest ones and B and the D were the
shortest.
In the
last part of the experiment the x y components are as follows:
The top one was (12.6
cm,12.1 cm) the distance between the x axis and the angle of the
rubber band is 3 cm.
The angle I came up with, by doing a reverse tangent was -26.57
degrees. The bottom
right one was (-10.2 cm,-11.3 cm) and the distance between was 4.5 cm.
The angle for
this one was 47.73 degrees.
This is all I have for this experiment.
Here is a list of my raw data:
The location of my point in quadrant 1 is (7.4,7.6).
Quadrant 2 (6.4,7.2). The one on the y
axis is (0,-10.2). Now these are measured from
the graph but I don't know how else to get
the points from the intersect of the line of
force.
I do not know the set number of my rubber bands but they are the same ones that I
used in
the mini expt 3 which are in order 1,2 and 3. The rubber bands align with the
quadrant
numbers. The length of 1 is 11.2 cm ,2 is 10.1 cm and 3 is 11.4 cm. After
looking at the
scale I found these figures for the force exerted on the rubber bands.
1 is 3.31 N, 2 is
2.41 N and 3 is 3.5 Newtons.
The length of my force vectors are
-1.3 cm in the x direction, 1.7 cm in the x direction and
-2.5 cm in the y
direction.
The total of my force vectors are in q1 1.65, 2.35 and 1.7 cm. In q2 1.6,
2.1 and 1.3 cm.
And the y axis is of course just 2.4 cm.
As far as the rest of this I
have the angles of the three and they are q1 is 45.8 deg, q2 is
48.4 deg and of course
the y axis is 0.
As far as the rest of the shetching of the vectors everything came
pretty close to what I
had calculated. When I used the pythagorean thereom, my work
checked out pretty close but
not exact. I found this to be very difficult in the way
of all of the calculations. If I'm
missing anything let me know.