course Phy 121 HK}ɷyDRassignment #001
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11:08:56 In terms of the equations of motion why do we expect that a * `ds is proportional to the change in v^2, and why do we then expect that the change in v^2 is proportional to Fnet `ds?
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RESPONSE --> constant accel * the rate at which 'ds is reached is proportional to velocity confidence assessment: 1
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11:10:17 How do our experimental results confirm or refute this hypothesis?
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RESPONSE --> confidence assessment: 0
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gk㞲ѷF assignment #008 008. Using the Acceleration of Gravity Physics I 06-25-2007
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10:11:31 `q001. The accepted value of the acceleration of gravity is approximately 980 cm/s^2 or 9.8 m/s^2. This will be the acceleration, accurate at most places within 1 cm/s^2, of any object which falls freely, that is without the interference of any other force, near the surface of the Earth. If you were to step off of a table and were to fall 1 meter without hitting anything, you would very nearly approximate a freely falling object. How fast would you be traveling when you reached the ground?
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RESPONSE --> v0=0 'ds=1m aAve='dv/'dt we need to know how long it takes to fall that one meter.. v=v0+at v=0 + at it seems we lack a little info, either a or t. i'm probably wrong... confidence assessment: 0
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10:18:32 `q002. If you jump vertically upward, leaving the ground with a vertical velocity of 3 m/s, how high will you be at the highest point of your jump? Note that as soon as you leave the ground, you are under the influence of only the gravitational force. All the forces that you exerted with your legs and other parts of your body to attain the 3 m/s velocity have done their work and are no longer acting on you. All you have to show for it is that 3 m/s velocity. So as soon as you leave the ground, you begin experiencing an acceleration of 9.8 m/s^2 in the downward direction. Now again, how high will you be at the highest point of your jump?
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RESPONSE --> v0=3m/s vf=0 a= -9.80/m/s^2 i would use the equation 'ds=vAve * 'dt so we know the vAve would be 1.5 m/s all we need to do is figure out the time. and i don't know how to do that confidence assessment: 0
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10:28:21 `q003. If you roll a ball along a horizontal table so that it rolls off the edge of the table at a velocity of 3 m/s, the ball will continue traveling in the horizontal direction without changing its velocity appreciably, and at the same time will fall to the floor in the same time as it would had it been simply dropped from the edge of the table. If the vertical distance from the edge of the table to the floor is .9 meters, then how far will the ball travel in the horizontal direction as it falls?
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RESPONSE --> v0=3m/s a=9.80m/s^2 'ds=.9m vf=0 'dt=-3m/s / (9.8m/s^2) = -.3sec this is what i've figured out so far. now i'm lost a little confidence assessment: 0
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