cq_1_021

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Phy 121

Your 'cq_1_02.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

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The problem:

A ball starts with velocity 4 cm/sec and ends with a velocity of 10 cm/sec.

What is your best guess about the ball's average velocity?

answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):

7 cm/sec

I only chose this because it's in the middle of 4 and 10.

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Without further information, why is this just a guess?

answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):

We are not given any information on how much distance was covered by the ball.

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If it takes 3 seconds to get from the first velocity to the second, then what is your best guess about how far it traveled during that time?

answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):

There are two ways to go about this:

1: Split the time into 3 events. For 1 second the ball traveled 4 cm. For 1 second the ball traveled 7 cm. For the final 1 second the ball traveled 10 cm. So the ball traveled 21 cm in 3 seconds.

2: My guess of the average velocity was 7 cm/sec, so 7 cm/sec * 3 sec = 21 cm.

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At what average rate did its velocity change with respect to clock time during this interval?

answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):

Average rate = Average velocity / average clock time, so Average Rate = (10 cm/s - 4 cm/s) / 3 seconds = 2 cm/s^2

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1

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10 - 15 minutes

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&#Very good responses. Let me know if you have questions. &#

&#See any notes I might have inserted into your document. If there are no notes, this does not mean that your solution is completely correct.

Then please compare your solutions with the expanded discussion at the link

Solution

Self-critique your solutions, if this is necessary, according to the usual criteria. Insert any revisions, questions, etc. into a copy of this posted document. Mark any insertions with &&&& so they can be easily identified.

If your solution is completely consistent with the given solution, you need do nothing further with this problem. &#

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