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Phy 121
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The problem:
A ball accelerates at 8 cm/s^2 for 3 seconds, starting with velocity 12 cm/s.
What will be its velocity after the 3 seconds has elapsed?
answer/question/discussion: ->->->->->->->->->->->-> :
36 cm/s. I have a low confidence on this because I used a simple method. If the velocity starts at 12 cm/s and increases by 8 cm/s every second then the final velocity is 12 cm/s + (8 cm/s * 3) = 36 cm/s
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Assuming that acceleration is constant, what will be its average velocity during this interval?
answer/question/discussion: ->->->->->->->->->->->-> :
(12 cm/s + 36 cm/s) / 2 = 24 cm/s = vAve. Again this does not feel right to me. I simply added the intial velocity and the final velocity and divided by 2 to get the Average Velocity.
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How far will it travel during this interval?
answer/question/discussion: ->->->->->->->->->->->-> :
72 centimeters. I drew a linear graph of velocity vs. clock time with points (0 sec, 12 cm/s) and (3 sec, 36 cm/s). I found the area of the trapezoid beneath the line and this area was the distance traveled. [The trapezoid was a rectangle with demensions 3 * 12 and a right triangle with a base and height of 3 and 24 respectively.]
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8-10 min
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Solution
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