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Phy 121
Your 'cq_1_07.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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10 min
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A ball falls freely from rest at a height of 2 meters. Observations indicate that the ball reaches the ground in .64 seconds.
Based on this information what is its acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
v0 = 0 m/s, 'dt = .64 seconds, 'ds = -2 meters. vAve = -2 m / .64 sec = -3.125 m/s.
vAve = (vf + v0) / 2, vf = vAve * 2 = -6.25 m/s.
Acceleration = (-6.25 m/s - 0 m/s) / .64 seconds = 9.76 m/s^2
My velocities are negative because the object is falling down.
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Is this consistent with an observation which concludes that a ball dropped from a height of 5 meters reaches the ground in 1.05 seconds?
answer/question/discussion: ->->->->->->->->->->->-> :
v0 = 0 m/s, 'dt = 1.05 sec, 'ds = -5 m, vAve = -5 m / 1.05 s = -4.76 m/s
vf = vAve * 2 = -9.52 m/s
Acceleration = -9.52 m/s / 1.05 s = 9.07 m/s^2
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Are these observations consistent with the accepted value of the acceleration of gravity, which is 9.8 m / s^2?
answer/question/discussion: ->->->->->->->->->->->-> :
Unless I made mistakes these answers are not exactly consistent, but they are fairly close.
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&#Your work looks very good. Let me know if you have any questions. &#