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Phy 121
Your 'cq_1_11.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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Answer the following based on Newton's Second Law:
How much net force is required to accelerate a 12 kg mass at 3 m/s^2?
answer/question/discussion: ->->->->->->->->->->->-> :
If Fnet = m * a then it requires 12 kg * 3 m/s^2 or 36 Newtons
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What would be the acceleration of a 4 kg mass subject to a net force of 20 Newtons?
answer/question/discussion: ->->->->->->->->->->->-> :
a = Fnet / m so a = 20 Newtons / 4 kg = 5 m/s^2
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If you exert a force of 20 Newtons on a 10-kg object and it accelerates in the direction of your force at 1.5 m/s^2, then how do you know there are other forces acting on the object besides your own?
answer/question/discussion: ->->->->->->->->->->->-> :
Because according to Newton's Second Law an object of 10 kg should accelerate 2 m/s^2 when 20 Newtons of force, but since it only accelerates 1.5 m/s^2 then there must be an opposing force of 5 Newtons.
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What is the total of all those forces and in what direction does this total act?
answer/question/discussion: ->->->->->->->->->->->-> :
There is 20 Newtons of Force in one direction and 5 Newtons of Force in the opposite direction.
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15 min
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&#This looks very good. Let me know if you have any questions. &#