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Phy 121
Your 'cq_1_16.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A rubber band has no tension until it reaches a length of 7.5 cm. Beyond that length its tension increases by .7 Newtons for every additional centimeter of length.
What will be its tension if its endpoints are at the points (5 cm, 9 cm) and (10 cm, 17 cm) as measured on an x-y coordinate system?
answer/question/discussion: ->->->->->->->->->->->-> :
The length of the band is then sqrt[(17 cm - 9 cm)^2 + (10 cm - 5 cm)^2] = 9.43 cm; 9.43 cm - 7.5 cm = 1.93 cm; so .7 N * 1.93 cm = a Tension of 1.4 N
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What is the vector from the first point to the second?
answer/question/discussion: ->->->->->->->->->->->-> :
It is the length of the rubber band (i think)
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What is the magnitude of this vector?
answer/question/discussion: ->->->->->->->->->->->-> :
9.43 cm
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What vector do you get when you divide this vector by its magnitude? (Specify the x and y components of the resulting vector).
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Im not exactly sure what this is asking. The length of the vector / its magnitude would be 1 in all cases (if im not mistaken).
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The new vector should have magnitude 1. When you divide a vector by its magnitude the result is a vector with magnitude 1. We call a vector of magnitude 1 a unit vector. What vector do you get when you multiply this new vector (i.e., the unit vector) by the tension?
answer/question/discussion: ->->->->->->->->->->->-> :
9.43 cm / 1.35 N = 6.98 cm/N
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What are the x and y components of the new vector?
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Im not fully familiar with vectors, although they seem easy enough I feel like im missing out on some things.
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This new vector is called the tension vector. It is a force vector which represents the tension. A force vector can be specified by its components, or equivalently by its magnitude and direction.
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Something apparently went haywire with the form, and your work got cut off at this point.
You're doing OK, but you'll probably need the discussion at the link below to put it all together.
Do submit a revision.
&#See any notes I might have inserted into your document, and before looking at the link below see if you can modify your solutions. If there are no notes, this does not mean that your solution is completely correct.
Then please compare your old and new solutions with the expanded discussion at the link
Solution
Self-critique your solutions, if this is necessary, according to the usual criteria. Insert any revisions, questions, etc. into a copy of this posted document. Mark any insertions with &&&& so they can be easily identified.If your solution is completely consistent with the given solution, you need do nothing further with this problem. &#