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Phy 121
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A steel ball of mass 60 grams, moving at 80 cm / sec, collides with a stationary marble of mass 20 grams. As a result of the collision the steel ball slows to 50 cm / sec and the marble speeds up to 70 cm / sec.
Is the total momentum of the system after collision the same as the total momentum before?
answer/question/discussion: ->->->->->->->->->->->-> :
Momentum before = 60g * 80 cm/s + 20g * 0 cm/s = 4800g cm/s
Momentum after = 60g * 50 cm/s + 20g * 70 cm/s = 4400g cm/s
The momentum before and after is not the same.
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What would the marble velocity have to be in order to exactly conserve momentum, assuming the steel ball's velocities to be accurate?
answer/question/discussion: ->->->->->->->->->->->-> :
It would have to be 90 cm/s. This would make teh Momentum After = 60g * 50 cm/s + 20g * 90 cm/s = 4800g cm/s
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8 min
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