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Phy 121
Your 'cq_1_25.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A steel ball of mass 110 grams moves with a speed of 30 cm / second around a circle of radius 20 cm.
What are the magnitude and direction of the centripetal acceleration of the ball?
answer/question/discussion: ->->->->->->->->->->->-> :
The magnitude of Centripetal Acceleration is 30^2 cm/s / 20 cm = 45 cm/s^2. I do not know however how to figure out the direction of the acceleration. I think it is directed right back at the center of the circle, I don't recall where I got that idea.
'Centripetal' means 'toward the center', so your idea was correct.
The reason isn't too complicated, but you don't need to know the reasoning for your course (it involves properties of circles and isosceles triangle).
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What is the magnitude and direction of the centripetal force required to keep it moving around this circle?
answer/question/discussion: ->->->->->->->->->->->-> :
F = .110 kg * .45 m/s^2 = 0.0495 N
Again I am not sure how to find the direction.
Was I right in changing the units from grams to kg and cm to meters?
g cm / s^2 is a force unit also, called the 'dyne'.
However changing to kg and m gave you the units in the more familiar unit 'Newtons'.
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&#Very good responses. Let me know if you have questions. &#