cq_1_271

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Phy121

Your 'cq_1_27.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

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A ball of mass 400 grams is immersed in water. The ball is suspended in the water by a rubber band chain which exerts a tension force of 2.5 Newtons on the ball.

What is the weight of the ball?

answer/question/discussion: ->->->->->->->->->->->-> :

Weight = mass * gravity = .4 kg * 9.8 m/s^2 = 3.92 N

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What is the buoyant force on the ball?

answer/question/discussion: ->->->->->->->->->->->-> :

At Equlibrium, Bouyancy Force + Tension force + Weight of Ball = 0 N

Bouyancy Force + 2.5 N - 3.92 N = 0, Bouyancy force = 1.42 N

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What therefore must be its volume?

answer/question/discussion: ->->->->->->->->->->->-> :

If the weight of the water moved must equal the weight of the ball, and if water has a density of 1000 kg / m^3 then its weight is 9800 N / m^3. So 'V' units of 9800 N / m^3 water = 1.42 N, Volume = 1.42 N / 9800 N/m^3 = 145 cm^3

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What is its density?

answer/question/discussion: ->->->->->->->->->->->-> :

Density = m/v = 400 g / 145 cm^3 = 2.75 g/cm^3

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&#Very good responses. Let me know if you have questions. &#

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