Assignment 18 23

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course Mth 158

7/23/13 12:50 pm

If your solution to stated problem does not match the given solution, you should self-critique per instructions at http://vhcc2.vhcc.edu/dsmith/geninfo/labrynth_created_fall_05/levl1_22/levl2_81/file3_259.htm.

Your solution, attempt at solution:

If you are unable to attempt a solution, give a phrase-by-phrase interpretation of the problem along with a statement of what you do or do not understand about it. This response should be given, based on the work you did in completing the assignment, before you look at the given solution.

018. `* 18

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Question: * 2.3.34 / 30 (was 2.3.24). Slope 4/3, point (-3,2)

Give the three points you found on this line and explain how you obtained them.

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Your solution:

To find three more points, I had to first graph the first point. Then I was able to use the slope, 4/3, to locate the others. Slope = rise/run so from the first point I could go up 4 points and over 3 points to find a second point, for example. The three additional points that I found (in ascending order) were (-6, -2), (0, 6), and (3, 10)

confidence rating #$&*: 3

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Given Solution:

* * STUDENT SOLUTION:

(-3,2) slope 4/3. Move 3 units in the x direction, 4 in the y direction to get

((-3+3), (2+4)), which simplifies to

(0,6)

(-3,2) slope 4/3 = -4/-3 so move -3 units in the x direction and -4 in the y direction to get

((-3-3), (2-4)) which simplifies to

(-6,-2)

From (0,6) with slope 4/3 we move 4 units in the y direction and 3 in the x direction to get

((0+3), (6+4)), which simplifies to

(3,10). The three points I obtained are

(-6,-2), (0,6), (3,10).

* 2.3.40 / 36 (was 2.3.30). Line thru (-1,1) and (2,2) **** Give the equation of the line and explain how you found the equation.

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Your solution:

First I had to find m

m = (y2 - y1) / (x2 - x1)

m = (2 - 1) / (2 + 1)

m = 1/3

Then I had to find the point-slope form [ y - y1 = m (x - x1) ] using one of the given points

m = 1/3 x1 = 2 y1 = 2

y - 2 = (1/3) (x - 2)

y - 2 = 1/3x - 2/3

y = 1/3x + 4/3

confidence rating #$&*: 3

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Given Solution:

* * STUDENT SOLUTION: The slope is m = (y2 - y1) / (x2 - x1) = (2-1)/(2- -1) = 1/3.

Point-slope form gives us

y - y1 = m (x - x1); using m = 1/3 and (x1, y1) = (-1, 1) we get

y-1=1/3(x+1), which can be solved for y to obtain

y = 1/3 x + 4/3.

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Self-critique (if necessary): OK

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Self-critique Rating: Ok

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Question: * 2.3.54 / 46 (was 2.3.40). x-int -4, y-int 4 * * ** What is the equation of the line through the given points and how did you find the equation?

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Your solution:

Find the x-int by y = 0 ; y-int by x = 0

So point 1 = (-4, 0) and point 2 = (0, 4)

m = (y2 - y1) / (x2 - x1)

m = (4 - 0) / (0 + 4)

m = 4/4

m = 1

m = 1 x1 = 0 y1= 4

y - y1 = m (x - x1)

y - 4 = 1 (x - 0)

y - 4 = x

y = x + 4

confidence rating #$&*: 3

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Given Solution:

* * STUDENT SOLUTION: The two points are (0, 4) and (4, 0). The slope is therefore m=rise / run = (4-0)/(0+4) = 1.

The slope-intercept form is therefore y = m x + b = 1 x + 4, simplifying to

y=x+4.

STUDENT QUESTION

I obtained

-x + y = 4 or y = x + 4.

I followed the example in the book which leaves 2 solutions (example problem 2.3.51) Did I do it correctly?

INSTRUCTOR RESPONSE

Both your solutions represent the same line, and both are correct.

y = 1x + 4 means the same thing as y = x + 4; we rearrange this to -x + y = 4 (just subtract x from both sides).

-x + y = 4 is a 'standard form' of the equation of this line.

y = x + 4 is the 'slope-intercept' form of the equation.

You don't need to know this, but still another 'standard form' is obtained by subtracting 4 from both sides of the equation -x + y = 4, giving us

-x + y - 4 = 0.

In this form we often want the coefficient of x to be positive, so we multiply both sides by -1 to get

x - y + 4 = 0.

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Self-critique (if necessary): OK

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Self-critique Rating: OK

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Question: * 2.3.76 / 56 (was 2.4.48). y = 2x + 1/2. **** What are the slope and the y-intercept of your line and how did you find them?

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Your solution:

The slope intercept form of a line is y = mx + b where m = slope and b = y intercept

So, for this equation y = 2x + 1/2, m = 2 and b = 1/2

confidence rating #$&*: 3

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Given Solution:

* * the y intercept occurs where x = 0, which happens when y = 2 (0) + 1/2 or y = 1/2. So the y-intercept is (0, 1/2).

The slope is m = 2.**

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Self-critique (if necessary): OK, I did not put the y-intercept in point form, but I felt it was unnecessary as the x = 0 should be understood

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Self-critique Rating: 3

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Question: * 2.3.62 / 22 (was 2.4.18) Parallel to x - 2 y = -5 containing (0,0) **** Give your equation for the requested line and explain how you obtained it.

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Your solution:

First, you must put it in slope-intercept form

y = mx + b

x - 2y = - 5

-2y = - x - 5

y = 1/2x + 5/2

So, m = 1/2

Now you must put it in point-slope form using the slope of the first line, but the new point of the second line

y - y1 = m (x - x1)

m = 1/2 x1 = 0 y1 = 0

y - 0 = 1/2 (x - 0)

y = 1/2x

confidence rating #$&*: 3

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Given Solution:

* * The equation x - 2y = -5 can be solved for y to give us

y = 1/2 x + 5/2.

A line parallel to this will therefore have slope 1/2.

Point-slope form gives us

y - 0 = 1/2 * (x - 0) or just

y = 1/2 x. **

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Self-critique (if necessary): OK

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Self-critique Rating: OK

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Question: * 2.3.68 / 28 (was 2.4.24) Perpendicular to x - 2 y = -5 containing (0,4) **** Give your equation for the requested line and explain how you obtained it.

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Your solution:

y = mx + b

x - 2y = -5

-2y = -x -5

y = 1/2x + 5/2

m = 1/2, so must find the negative converse of this slope to use for the perpendicular line

The new m is m = -2

m = -2 x1= 0 y1 = 4

y - y1 = m (x -x1)

y - 4 = -2 (x - 0)

y - 4 = -2x

y = -2x + 4

confidence rating #$&*: 3

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Given Solution:

* * The equation x - 2y = -5 can be solved for y to give us

y = 1/2 x + 5/2.

A line perpendicular to this will therefore have slope -2/1 = -2.

Point-slope form gives us

y - 4 = -2 * (x - 0) or

y = -2 x + 4. **

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Self-critique (if necessary): OK

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Self-critique Rating: OK"

Self-critique (if necessary):

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Self-critique rating:

&#Good responses. Let me know if you have questions. &#