#$&*
course Phy 201
3/1/11 around 12:56pm
Reason out the quantities v0, vf, Dv, vAve, a, Ds and Dt: If an object’s velocity changes at a uniform rate from 8 cm/s to 11 cm/s as it travels 38 cm, then what is the average acceleration of the object?v0= 8cm/s
vf= 11cm/s
`dv= 11-8= 3cm/s
(8+11)/2= 9.5cm/s vAve
38cm/ 9.5cm/s= 4sec
(3cm/s)/(4sec)= 0.75cm/s^2 aAve
Using the equations which govern uniformly accelerated motion determine vf, v0, a, Ds and Dt for an object which accelerates through a distance of 38 cm, starting from velocity 8 cm/s and accelerating at .75 cm/s/s.
@& Good reasoning, but you also need to solve using the equations of uniformly accelerated motion.*@