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Phy 201
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A ball falls freely from rest at a height of 2 meters. Observations indicate that the ball reaches the ground in .64 seconds.
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Based on this information what is its acceleration?
answer/question/discussion: ->->->->->->->->->->->-> scussion:
a= `dv/`dt `dt= 0.64sec
2m/0.64sec= 3.125m/s this is the vAVe 3.125m/s * 2m = 6.25m/(0.64sec) = 9.77m/s^2 this is the acceleration
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Is this consistent with an observation which concludes that a ball dropped from a height of 5 meters reaches the ground in 1.05
seconds?
answer/question/discussion: ->->->->->->->->->->->-> scussion:
No, because the average velocity for this ball would be 5m/1.05sec= 4.76m/s compared to 3.125m/s
@& Dropped from different heights, you would expect different average velocities.
The question is related to the acceleration, which you have not found for the second ball.*@
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Are these observations consistent with the accepted value of the acceleration of gravity, which is 9.8 m / s^2?
answer/question/discussion: ->->->->->->->->->->->-> scussion:
From what I calculated it seems that yes the observations are consistent. If I round my value up I get 9.8m/s^s
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@& Good calculation on the first acceleration, but you need to calculate the second before answering the remaining questions.
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