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Phy 201
Your 'cq_1_10.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A pendulum requires 2 seconds to complete a cycle, which consists of a complete back-and-forth oscillation (extreme point to
equilibrium to opposite extreme point back to equilibrium and finally to the original extreme point). As long as the amplitude of the
motion (the amplitude is the distance from the equilibrium position to the extreme point) is small compared to the length of the pendulum,
the time required for a cycle is independent of the amplitude.
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How long does it take to get from one extreme point to the other, how long from an extreme point to equilibrium, and how long to
go from extreme point to equilibrium to opposite extreme point and back to equilibrium?
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answer/question/discussion: ->->->->->->->->->->->-> scussion:
2sec/cycle 1cycle= extreme to equil, to opposite extreme back to equil, equil to final extreme
Their are 2 extreme points 2/2 = 1 it will take 1 second to get from one extreme point to the other. 2sec/4= 0.5sec to go from extreme
point to equilibrium. 0.5* 3= 1.5second to go from extreme to equil, to opposite extreme, then back to equil.
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What reasonable assumption did you make to arrive at your answers?
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answer/question/discussion: ->->->->->->->->->->->-> scussion:
It was assumed that the pendulum went the same distance from one extreme position to the other and back. If the distance was shorter the
times would be off.
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15 minutes
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&#Very good responses. Let me know if you have questions. &#