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Phy 201
Your 'cq_1_12.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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Masses of 5 kg and 6 kg are suspended from opposite sides of a light frictionless pulley and are released.
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What will be the net force on the 2-mass system and what will be the magnitude and direction of its acceleration?
answer/question/discussion: ->->->->->->->->->->->-> scussion:
5kg*9.8m/s^2= 49N 6kg*9.8m/s^2 = 58.8N The system will be going in the direction of the 6kg mass, I will call this the
positive direction. The Net force on the system will be 58.8N-49N= 9.8N Net Force
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If you give the system a push so that at the instant of release the 5 kg object is descending at 1.8 meters / second, what will
be the speed and direction of motion of the 5 kg mass 1 second later?
answer/question/discussion: ->->->->->->->->->->->-> scussion:
I know that the velocity will be slower 1 second later, but I am having trouble reasoning out how to calculate the values. The
object most likely slow down and start moving in the opposite direction since the 5kg mass doesn't have as much force as the 6kg mass.
@& Your instincts are correct.
You need to first calculate the acceleration, based on your correct 9.8 N net force. The total mass is 11 kg.
Having calculated the acceleration of the system you need to consider by how much the velocity will change in 1 second.
Check the link at the end for more details.*@
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During the first second, are the velocity and acceleration of the system in the same direction or in opposite directions, and
does the system slow down or speed up?
answer/question/discussion: ->->->->->->->->->->->-> scussion:
The velocity and acceleration are in the same direction momentarily. The system is slowing down, then speeding up in the opposite
direction.
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20 Minutes
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self-critique rating
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@& `c121*@