course ????O???|??z???assignment #019
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13:21:55 2.4.30 (was 2.3.24). Slope 4/3, point (-3,2) Give the three points you found on this line and explain how you obtained them.
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RESPONSE --> The 4 points altogether are (-6, -2), (-3, 2), (0, 6) and (3, 10) since the slope is 4/3, every rise of four also has a run of three, same with -4 and -3. confidence assessment: 2
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13:22:18 STUDENT SOLUTION: (-3,2) slope 4/3. Move 3 units in the x direction, 4 in the y direction to get ((-3+3), (2+4)), which simplifies to (0,6) (-3,2) slope 4/3 = -4/-3 so move -3 units in the x direction and -4 in the y direction to get ((-3-3), (2-4)) which simplifies to (-6,-2) From (0,6) with slope 4/3 we move 4 units in the y direction and 3 in the x direction to get ((0+3), (6+4)), which simplifies to (3,10). The three points I obtained are (-6,-2), (0,6), (3,10).
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RESPONSE --> ok self critique assessment: 3
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13:27:51 query 2.4.36 (was 2.3.30). Line thru (-1,1) and (2,2) **** Give the equation of the line and explain how you found the equation.
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RESPONSE --> Using the slope formula (y2 - y1) / (x2 - x1) 1-2 / -1-2 = 1/3 Using the equation of a line y - y1 = m(x - x1) y - 1 = 1/3 (x + 1) y -1 = (1/3)x + 1/3 y = (1/3)x + 4/3 confidence assessment: 2
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13:28:00 STUDENT SOLUTION: The slope is m = (y2 - y1) / (x2 - x1) = (2-1)/(2- -1) = 1/3. Point-slope form gives us y - y1 = m (x - x1); using m = 1/3 and (x1, y1) = (-1, 1) we get y-1=1/3(x+1), which can be solved for y to obtain y = 1/3 x + 4/3.
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RESPONSE --> ok self critique assessment: 3
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13:33:40 2.4.46 (was 2.3.40). x-int -4, y-int 4 **** What is the equation of the line through the given points and how did you find the equation?
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RESPONSE --> Using the slope formula (y2 - y1) / (x2 - x1) (0 -4) / (-4 -0) = -4/-4 = 1 Using the equation of a line y - y1 = m(x - x1) y - 0 = 1(x -4) y = x-4 confidence assessment: 2
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13:34:37 STUDENT SOLUTION: The two points are (0, 4) and (4, 0). The slope is therefore m=rise / run = (4-0)/(0+4) = 1. The slope-intercept form is therefore y = m x + b = 1 x + 4, simplifying to y=x+4.
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RESPONSE --> I didn't change the sign on the 4... understood. self critique assessment:
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13:35:41 2.4.56 (was 2.4.48). y = 2x + 1/2. **** What are the slope and the y-intercept of your line and how did you find them?
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RESPONSE --> 1/2 is the y intercept, and 2 is the slope confidence assessment: 2
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13:35:56 ** the y intercept occurs where x = 0, which happens when y = 2 (0) + 1/2 or y = 1/2. So the y-intercept is (0, 1/2). The slope is m = 2.**
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RESPONSE --> understood self critique assessment: 3
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???GwX?h??????e??? assignment #018 018. `query 18 College Algebra 07-04-2008