course phy121
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A projectile leaves the edge of a table and falls freely a distance of 103 cm to the floor. It travels a horizontal distance of 13.8 cm during its fall. How long does it take to fall and what is its horizontal velocity during the fall?For this problem we have the following inform
`ds=103 cm
a = 980 cm/s^2 for gravitional acceleration as the object falls
v0 = 0 since it will start from a vertical velocity of zero
From this information, we can determine `dt using the following
`ds=v0`dt + .5a`dt^2 since v0 = 0, we can simplify the term to solve for `dt
`dt =`sqrt(2`ds/a)
`dt = `sqrt(206cm/980cm/s^2)
`dt = .46 seconds
For the horizontal velocity, we traveled 13.8 cm in approximately .46 seconds. We divide the 13.8 cm/.46 s to find its horizontal velocity of 30 cm/s.
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