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Phy 201
Your 'cq_1_10.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A pendulum requires 2 seconds to complete a cycle, which consists of a complete back-and-forth oscillation (extreme point to equilibrium to opposite extreme point back to equilibrium and finally to the original extreme point). As long as the amplitude of the motion (the amplitude is the distance from the equilibrium position to the extreme point) is small compared to the length of the pendulum, the time required for a cycle is independent of the amplitude.
• How long does it take to get from one extreme point to the other, how long from an extreme point to equilibrium, and how long to go from extreme point to equilibrium to opposite extreme point and back to equilibrium?
It takes the pendulum 1 second to get from one extreme point to the other (original position to the first extreme). It takes .5 seconds to get from one extreme point to equilibrium. It takes 1.5 seconds to go from extreme point to equilibrium to opposite extreme point and back to equilibrium.
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answer/question/discussion: ->->->->->->->->->->->-> :
• What reasonable assumption did you make to arrive at your answers?
I sketched a diagram for this probably and basically divided the pendulum into fourths. From the original starting extreme position to equilibrium, equilibrium to extreme, extreme back to equilibrium, and equilibrium back to the original starting extreme position. Then, I figured that if the pendulum takes 2 seconds for it to complete a full cycle (original extreme, then from extreme back to original) then it takes about .5 seconds to complete each fourth.
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&#Very good responses. Let me know if you have questions. &#