cq_1_111

#$&*

Phy 201

Your 'cq_1_11.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

** **

Answer the following based on Newton's Second Law:

• How much net force is required to accelerate a 12 kg mass at 3 m/s^2?

answer/question/discussion: ->->->->->->->->->->->-> :

F = m * a

F = 12 kg * 3 m/s^2

F = 36 N

#$&*

• What would be the acceleration of a 4 kg mass subject to a net force of 20 Newtons?

answer/question/discussion: ->->->->->->->->->->->-> :

F = m * a

A = Fnet / m

A = 20 N / 4kg

A = 5 m/s^2

#$&*

• If you exert a force of 20 Newtons on a 10-kg object and it accelerates in the direction of your force at 1.5 m/s^2, then how do you know there are other forces acting on the object besides your own?

answer/question/discussion: ->->->->->->->->->->->-> :

a = Fnet / m

a = 20N / 10kg

a = 2 m/s^2

I know there are other forces acting on the object besides my own because the calculations show that the object should be moving at an acceleration of 2 m/s^2. Since it is only moving at 1.5 m/s^2, then there is an opposing force acting upon the object.

#$&*

• What is the total of all those forces and in what direction does this total act?

answer/question/discussion: ->->->->->->->->->->->-> :

If I am pushing with a force of 20 N and the acceleration of the object is 1.5 m/s^s, then we can figure out that the opposing force is -5 N because:

20 + (-5N) = 15 N

Fnet = 15N

#$&*

*#&!

&#Very good responses. Let me know if you have questions. &#